The sample size of 36 will produce the widest 95% confidence interval when estimating the population parameter option (b) is correct.
<h3>What are population and sample?</h3>
It is described as a collection of data with the same entity that is linked to a problem. The sample is a subset of the population, yet it is still a part of it.
We have:
A sample has a sample proportion of 0.3.
Level of confidence = 95%
At the same confidence level, the larger the sample size, the narrower the confidence interval.
As we have a 95% confidence interval the sample size should be lower.
The sample size from the option = 36 (lower value)
Thus, the sample size of 36 will produce the widest 95% confidence interval when estimating the population parameter option (b) is correct.
Learn more about the population and sample here:
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The answer is: 7/7
hope this helps :))
Answer:
A
Step-by-step explanation:
if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is
(x-x1)(x-x2)+(y-y1)(y-y2)=0
reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

center is (2,-4)
r=√(2²+(-4)²-(-14))
=√(4+16+14)
=√(34)
eq. of circle is (x-2)²+(y+4)²=34
or
(x²-4x)+(y²+8y)=14
(x²-4x+4)+(y²+8y+16)=14+4+16
(x-2)²+(y+4)²=34
Answer:
The probability is 0.003
Step-by-step explanation:
We know that the average
is:

The standard deviation
is:

The Z-score is:

We seek to find

For P(x>800) The Z-score is:



The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So

For P(x<200) The Z-score is:



The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So

Therefore



Step-by-step explanation:
a. The point estimate is the mean, 47 days.
b. The margin of error is the critical value times the standard error.
At 31 degrees of freedom and 98% confidence, t = 2.453.
The margin of error is therefore:
MoE = 2.453 × 10.2 / √32
MoE = 4.42
c. The confidence interval is:
CI = 47 ± 4.42
CI = (42.58, 51.42)
d. We can conclude with 98% confidence that the true mean is between 42.58 days and 51.42 days.
e. We can reduce the margin of error by either increasing the sample size, or using a lower confidence level.