Answer:
There is 7/15 left in the bag
Step-by-step explanation:
So, you need to find a common denominator between 3 and 5 which is 15
multiply the numerator and the denominator by 3 in 1/5. Then, multiply the numerator and the denominator by 5 in 1/3.
1/3*5=5/15
1/5*3=3/15
Add them together.
5/15+3/15=8/15
Lastly, subtract 15/15 by 8/15
15/15-8/15=7/15
Thanks for the points
~(￣▽￣)~ (～￣▽￣)～
<u><em>Have a Happy Thanksgiving!
</em></u>
F(x) = x^5 - x^3 + x
f'(x) = 5x^4 - 3x^2 + 1
f(3) = (3)^5 - (3)^3 + 3 = 243 - 27 + 3 = 219
f'(3) = 5(3)^4 - 3(3)^2 + 1 = 5(81) - 3(9) + 1 = 405 - 27 + 1 = 379
Let the required equation of the tangent line be
y = mx + c; where y = 219, m = 379, x = 3
219 = 379(3) + c = 1,137
c = 219 - 1,137 = -918
Therefore, required equation is
y = 379x - 918
I do believe it is answer c, but not 100% on that due to the fact that when i worked it i got c, but when i googled alot got other answers. sorry i know thats not much help
Answer:
It is a polynomial
Step-by-step explanation:
The given expression 
a polynomial.
Type: monomial or cubic
Degree: 3
