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never [62]
3 years ago
14

Two threads try to acquire the same resource at the same time and both are blocked. Then, they continually change their states i

n the same way and are continuously blocked. This condition is called
Computers and Technology
1 answer:
maksim [4K]3 years ago
7 0

Answer:

livelock.

Explanation:

"Two threads try to acquire the same resource at the same time and both are blocked. Then, they continually change their states in the same way and are continuously blocked. This condition is called" LIVELOCK.

The term ''livelock" in is a very good and a very important in aspect that is related to computing. LIVELOCK simply means a lock in which the process in denied multiple times. A perfect example is;

When a person A and a person meet on a very narrow path. Both person A and Person B will want to shift to a position which will allow each of them to pass(This are the processes Person A and B wants to take), so if the two now move to the same exact position instead of moving in an opposite direction then, we will say that we have a LIVELOCK.

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3 years ago
A personal phone directory contains room for first names and phone numbers for 30 people. Assign names and phone numbers for the
Fynjy0 [20]

Answer:

# include <iostream.h>

# include <stdio.h>

# include <string.h>

using namespace std;

class citizen

{      

    int i;

    public string name[30];

    public long int phonenumber[30];

    public void addindividual(string name1)

     {      

           If (i<=30)

            {     int flag=0;

                  for(int j=0; j<=i;j++)

                  {

                     if (strcmp(name[i], name1)

                      {

                          flag=1;

                      }

                     else

                     {  

                           flag=0;

                     }

                  }

                  If (flag)

                 {

                  if (i<30)

                  {

                  for(j=i+1;j<=30; j++)

                  {

                        cout<<"Enter the name:"; getchar(name[j]);

                        cout<<"Enter the phone number:"; cin>>phonenumber[j];

                         i++;

                   }

                  else  

                   {

                        cout<<"The person already exists";

                        exit();

                   }

              }

            else

             {

                 cout<<"array is full:";

                 exit();

             }

     }

}

Void main()

{

     string str;

    cout<<" Enter name:";

    getline(cin, str); ;

     citizen c1=new citizen();

     c1.addindividual(name1);

}

Explanation:

With a little more effort you can make the program allow the user to enter any number of details, but less than 30 overall. We have used here flag, and as a programmer we know why we use the Flag. It is used to check whether certain Boolean condition is fulfilled or not. Here, we are checking whether a given name is present in the array of names, and if it is not present, we add that to the list. And if the name is present, we print, it already exist.

4 0
3 years ago
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