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RUDIKE [14]
3 years ago
14

Solve the system of equations by using substitution.

Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

x = -3 , y = 2 thus D) is your answer

Step-by-step explanation by substitution:

Solve the following system:

{-9 = x - 3 y

6 - 2 x = 6 y

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{-9 = x - 3 y

6 - 2 x = 6 y

Hint: | Reverse the equality in -9 = x - 3 y in order to isolate x to the left hand side.

-9 = x - 3 y is equivalent to x - 3 y = -9:

{x - 3 y = -9

6 - 2 x = 6 y

Hint: | Solve for x.

Add 3 y to both sides:

{x = 3 y - 9

6 - 2 x = 6 y

Hint: | Perform a substitution.

Substitute x = 3 y - 9 into the second equation:

{x = 3 y - 9

6 - 2 (3 y - 9) = 6 y

Hint: | Expand the left hand side of the equation 6 - 2 (3 y - 9) = 6 y.

6 - 2 (3 y - 9) = (18 - 6 y) + 6 = 24 - 6 y:

{x = 3 y - 9

24 - 6 y = 6 y

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for y:

{x = 3 y - 9

24 - 6 y = 6 y

Hint: | Isolate y to the left hand side.

Subtract 6 y + 24 from both sides:

{x = 3 y - 9

-12 y = -24

Hint: | Solve for y.

Divide both sides by -12:

{x = 3 y - 9

y = 2

Hint: | Perform a back substitution.

Substitute y = 2 into the first equation:

Answer:  {x = -3 , y = 2

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Step-by-step explanation:

We are given that:

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Recall that:

\displaystyle \sin^2 \theta + \cos^2 \theta = 1

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Part 5.1.2

Recall that:

\displaystyle \begin{aligned}  \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &=   1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}

We can use the third form. Substitute:

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