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Svet_ta [14]
3 years ago
9

What is the balance of an investment after 2 years if the starting amount was 543300

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Since it is simple interest, you have to use the formula I = Prt.

(I is interest, P is principal (the starting amount), and r is the & rate as a decimal.

So, the interest would be

I = 543,300 (0.048) (2) = $52,156.80

The balance is the total amount.  The balance would be the starting amount plus the interest.

Balance = 543,300 + 52,156.80 = $595,456.80

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You have decided to invest $1000 in a savings bond that pays 4% interest, compounded semi-annually. What will the bond be worth
Evgen [1.6K]

Answer:

$2191.12

Step-by-step explanation:

We are asked to find the value of a bond after 10 years, if you invest $1000 in a savings bond that pays 4% interest, compounded semi-annually.

FV=C_0\times (1+r)^n, where,

C_0=\text{Initial amount},

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n = Number of periods.

Since interest is compounded semi-annually, so 'n' will be 2 times 10 that is 20.

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FV=\$1,000\times (1+0.04)^{20}

FV=\$1,000\times (1.04)^{20}

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FV=\$2191.1231430334194

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Therefore, the bond would be $2191.12 worth in 10 years.

3 0
3 years ago
What is the answer to (14x-35)/7=7
IceJOKER [234]
Your not being very discriptive... BUT if you are finding 'x'...
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