The opening course of the Dog Olympics involves the dogs running over a parabolic
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Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Person has the flu.
- Event B: Person got the flu shot.
The percentages associated with getting the flu are:
- 20% of 30%(got the shot).
- 65% of 70%(did not get the shot).
Hence:
The probability of both having the flu and getting the shot is:
Hence, the conditional probability is:
0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
To learn more about conditional probability, you can take a look at brainly.com/question/14398287
First, we combine the terms on the left side of the equation to simplify the equation. Then we divide both sides by -3. k then equals 1/3.
To check, we plug in our value for k into the original equation:
We found k to be 1/3, so for every instance of k, we plug in 1/3. To simplify, we combine the left side to get -1, and we combine the right side to get -1.
Since -1 = -1, our solution is correct.
The total weight of the other five items are 10.444 kg
<em>(round as you wish)</em>