The histogram is especially useful in comparing mean and median values of a variable. We have that 5.5+6+7+10+7.5+8+9.5+9+8.5+8+7+7.5+6+6.5+5.5=111.5 Since there are 15 values, their mean is 111.5/15=7.43 which is very close to the mean. We also have that 7 onservations are lower than 7.4 while 8 are bigger than 7.4; hence, the diagram is rather balanced and not left-skewed. We cannot tell immediately which one is larger since the values are too close. Any such random process can usually be approximated to a greater or smaller degree by a normal curve; the more points, the better. The histogram shows this (it is kind of a discrete normal curve); all points except 4 will be in this interval of bars.
Answer:
B. 2 3/4 lbs
Step-by-step explanation:
there ar 16 ticks on a scale, the pointer is on 12, meaning it is 12/16, whihc is answer b
Given:
The graph of a function 
.
To find:
The interval where 
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, for 
and 
.
The function between x=0 and x=3.6 lies below the x-axis. So, 
for 
.
Now,
For 
, the graph of h(x) is above the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
For 
, the graph of h(x) is below the x-axis. So, .
Only for the interval , we get .
Therefore, the correct option is A.
-6g + 36 = 12
36 = 12 + 6g
24 = 6g
4 = g
g = 4
