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3 years ago

What is the answer?

Mathematics

1 answer:

Fiesta28 [93]3 years ago

6 0

Answer:

6 y^2 sqrt(2)

Step-by-step explanation:

We know that sqrt(a) * sqrt(b) = sqrt(ab)

sqrt(12) sqrt(y^3) sqrt(6y)

sqrt(12*y^3*6y)

sqrt(72 y^4)

sqrt(36 *2 *y^4)

sqrt(36) sqrt(2) sqrt(y^4)

6 sqrt(2) y^2

6 y^2 sqrt(2)

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Please answer, will mark brainliest

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The answer is A. The sample space of an experiment or random trial is the set of all possible outcomes and results of that experiment, which means that they will be unique outcomes.

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David made a class banner out of a large rectangular piece of paper. He

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Given:

A triangular piece is cut out of a rectangular piece of paper to make the class banner.

To find:

The area of the class banner.

Solution:

The rectangular piece of paper is 14 inches long and $5+3=8$ inches wide.

From the given diagram, the triangle has a base length of the same 8 inches and has a height of $14-11=3$ inches long.

To determine the area of the banner, we subtract the area of the triangle from the area of the rectangle.

The area of a triangle $= \frac{1}{2} (b)(h).$

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The area of the class banner $= 112-12=100$ square inches.

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3 years ago

What are Constant of Proportionality?

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The constant that changes proportionality into equality...

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4 years ago

Find the X and Y intercepts of the graph x + 3y = 13

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Step-by-step explanation:

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3 years ago

The square of X varies inversely as the square root of Y and directly as the variable M. When M = 27 and Y = 16, then X = 9. Fin

irakobra [83]

Answer:

$Y = 441$

Step-by-step explanation:

Given

M = 27 when Y = 16 and X = 9

Required

Find Y when M = 7 and X = 2

We start by getting the algebraic representation of the given statement

$X^2 \alpha \frac{1}{\sqrt Y} \alpha M$

Convert the variation to an equation; we have

$X^2 = \frac{KM}{\sqrt Y}$

Where K is the constant of variation;

When M = 27; Y = 16; X = 9, the expression becomes

$9^2 = \frac{K * 27}{\sqrt{16}}$

This gives

$81 = \frac{k * 27}{4}$

Make K the subject of formula

$K = \frac{81* 4}{27}$

$K = \frac{324}{27}$

$K = 12$

Solving for Y when M = 7 and X = 2

Recall that $X^2 = \frac{KM}{\sqrt Y}$

Substitute values for K, M and X

$2^2 = \frac{12 * 7}{\sqrt{Y}}$

$4 = \frac{84}{\sqrt{Y}}$

Take square of both sides

$4^2 = (\frac{84}{\sqrt{Y}})^2$

$16 = \frac{7056}{Y}$

Make Y the subject of formula

$Y = \frac{7056}{16}$

$Y = 441$

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3 years ago