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ratelena [41]
2 years ago
12

A small business takes out a loan for $14,000 at 7% simple interest over the course of 4 years. What is the monthly payment?

Mathematics
1 answer:
inysia [295]2 years ago
7 0
Answer is d because I used that Calculator
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A sequence starts 1,5,9,13,17<br> What’s the formula for the nth term of this sequence??
worty [1.4K]

This is an arithmetic sequence, since it's pattern is +4.

n1 = 1

d = 4

n = 1 + (n-1)(4) <-------------- This is the formula for the nth term of the sequence.

6 0
3 years ago
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(The last 22 and 23)
quester [9]
1) 24
2) (-8)


Hope this helps
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3 years ago
What is two equivalent fractions for 16/48
olga_2 [115]
Hi , two equivalent fractions for 16/48 are 1/3 and 8/24. Equivalent fraction is a fraction that is the same but it has different numbers.
5 0
2 years ago
The formula m = 12,000 + 12,000rt 12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length
alexandr1967 [171]

Answer:

  $240

Step-by-step explanation:

Fill in the given numbers and do the arithmetic.

m=\dfrac{12,000+12,000rt}{12t}=\dfrac{12,000+12,000\cdot 0.04\cdot 5}{12\cdot 5}\\\\m=\dfrac{14,400}{60}=240

Keri's monthly loan payment is $240 per month.

3 0
3 years ago
Read 2 more answers
Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t
Amanda [17]

Answer:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

df = n-1= 22-1=21

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

\bar X=33.9 represent the sample mean

s=4.1 represent the sample standard deviation

n=22 sample size  

\mu_o =26 represent the value that we want to test

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:  

Null hypothesis:\mu \geq 36  

Alternative hypothesis:\mu < 36  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

Now we can calculate the critical value but first we need to find the degreed of freedom:

df = n-1= 22-1=21

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0
3 years ago
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