Hi friend,
f(x) = x²
g(x) = x+6
f(0) = 0² =0
g ( f(0) ) = f(0) +6
= 0+6 = 6
Hope this helps you!
I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.
We have to turn K into the limits of integration on our integrals.
Clearly 0 is the lower limit for all three of x, y and z.
Now we have to incorporate
x+y+z ≤ 1
Let's do the outer integral over x. It can go the full range from 0 to 1 without violating the constraint. So the upper limit on the outer integral is 1.
Next integral is over y. y ≤ 1-x-z. We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y. So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.
Similarly the inner integral goes from z=0 to z=1-x-y
We've transformed our integral into the more tractable

For the inner integral we get to treat x like a constant.

Let's expand that as a polynomial in y for the next integration,

The middle integration is



Expanding, that's

so our outer integral is

That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).


That's a surprise. You might want to check it.
Answer: 0
Answer:
Step-by-step explanation: if there are 500 pieces of paper and the entire stack is 1.875 inches tall, you devide the total height by 500. I know Deigo is wrong because you can easily reverse check his work by multiplying 0.015 by the total number of papers 500 you will get 7.5 which is not the height of the stack
1.875/500=0.00375
each piece of paper is 0.00375
Answer:
Step-by-step explanation:
Answer: The answer is 25
Step-by-step explanation:
First, You would add the two numbers together, which you get 155
Then, the degrees of a triangle is equal to 180. So you would subtract 155 from 189, and you should get 55.
Hope this helps :3