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3 years ago

The prism shown has a volume of 798 cm3.

Mathematics

1 answer:

a_sh-v [17]3 years ago

4 0

Answer:

10.5 cm

Step-by-step explanation:

Volume = base area × height

798 = (9.5 × 8) × height

height = 798/76

height = 10.5

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Rachel earned \$34$34 in 44 hours at her job today. She wants to know how much she could earn (e)(e) tomorrow if she works 1010

kari74 [83]

Answer:

Rachel will earn $85 in 10 hours.

Step-by-step explanation:

Rachel earned $34 in 4 hours at her job today.

Suppose, she will earn $x$ dollar in 10 hours tomorrow.

So, according to ratio of 'dollar' and 'hours', the equation will be.....

$\frac{34}{4}=\frac{x}{10}$

After cross multiplying, we will get.....

$4x= 34*10\\ \\ 4x= 340\\ \\ x=\frac{340}{4}=85$

Thus, Rachel will earn $85 in 10 hours.

6 0

3 years ago

Read 2 more answers

Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo

Shkiper50 [21]

Answer:

a) $P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335$

b) $P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452$

c) $P(X \geq 8) = 1-P(X$

d) $P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that $X \sim Poisson(\lambda=4)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda=4$ , $Var(X)=\lambda=2$ , $Sd(X)=2$

a. Compute both P(X≤4) and P(X<4).

$P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183$

$P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733$

$P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465$

$P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646$

$P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692$

b. Compute P(4≤X≤ 8).

$P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595$

$P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298$

$P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452$

c. Compute P(8≤ X).

$P(X \geq 8) = 1-P(X$

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

$P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

4 0

3 years ago

How many

AVprozaik [17]

Answer:the answer is

Step-by-step explanation:

First convert 7 1/2 to an improper fraction

15/2 ÷ 3/4

Division of fractions hold the first fraction replaces ÷ with x then flip the second fraction

15/2 x 4/3

Multiply the tops 15x4 =60

Over the bottoms multiplied together 2x3=6

60/6=10

10 people can be served that should help

6 0

3 years ago

Adjust the equation so the line passes through the points.

Karo-lina-s [1.5K]

Answer:

adjust the equation so the line passes through the points

6 0

2 years ago

5-1+2x(4x4-12)x8 explain

Romashka [77]

First, do what's in the paranthesis:

(4*4-12)

Multiplication first:

16-12

Then subtract:

We get:

5-1+2*4*8

Multiply:

2*4

Multiply, again:

8*8

We get:

5-1+64

Subtract:

5-1

Add:

4+64

Answer: 68

5 0

3 years ago

Read 2 more answers