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2 years ago

5

The function below can be used to calculate the cost of surfing the internet, f(m), which is based on a $10 initial charge and a

fee of $.15 per minute, m, till you sign off. f(m)=10+0.15m If Jon paid $40, how many minutes did he use the internet?

1 answer:

Sever21 [200]2 years ago

6 0

Biggie biggie biggie can’t you see sometime your word just hypnotize me

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The dimensions of a big dog house are 2 1/2 the dimensions of a small dog house. If the width of the small doghouse is 2 feet, w

Alchen [17]

The width of the big dog house is 2.5 times the small dog house.
multiply 2 by 2.5 to get your answer. hope this helps :)

6 0

3 years ago

Find two numbers such that the sum of their squares is 100. The square of the larger number is equal to the sum of the product o

Shtirlitz [24]

Answer with Step-by-step explanation:

Let x and y are two numbers

According to question

$x^2+y^2=100$ ....(1)

Suppose x is larger than y

$x^2=x(4y+8x)$

$x=4y+8x$

$x-8x=4y$

$-7x=4y$

$y=-\frac{7}{4}x$

Substitute the value of y

$x^2+(-\frac{7}{4}x)^2=100$

$x^2+\frac{49}{16}x^2=100$

$\frac{16x^2+49x^2}{16}=100$

$\frac{65}{16}x^2=100$

$x^2=\frac{16\times 100}{65}$

$x=\sqrt{\frac{1600}{65}}=\frac{40}{\sqrt{65}}=\frac{40}{65}\sqrt{65}=\frac{8}{13}\sqrt{65}$

$y=-\frac{7}{4}\times \frac{8}{13}\sqrt{65}=-\frac{14}{13}\sqrt{65}$

3 0

3 years ago

In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta

scoundrel [369]

Answer:

Tan(b°) = 3/4 = three fourths (C)

Step-by-step explanation:

Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°

We would apply SOHCAHTOA from trigonometry to determine the value for each sides.

For ∆JKL

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4

From the above we know the value of each sides of ∆JKL

Find attached the diagram of the above triangle (1)

∆JKL is dilated by a scale factor = 2

Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:

Opposite = 2(3) = 6

Adjacent = 2(4) = 8

Hypotenuse = 2(5) = 10

To find tan(b°) of the new triangle, we would apply tangent ratio

Tan(b°) = opposite/adjacent

Tan(b°) = 6/8

Tan(b°) = 3/4

Find attached the diagram for the new triangle (2)

Diagram 3 shows the drawing of both triangles together.

From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.

Therefore, tan(b°) = three fourths (C)

6 0

3 years ago

Question 2c: Which dog sitting service is better if you need 5 hours of service? Explain your answer PLEASE!

Juliette [100K]

Jacobs dog: $5 x 5 hours plus $ 12 service is $37
Jacks dog : $3 x 5 hours plus $18 service is $ 33
So it’s cheaper to go with jacks dog service

8 0

3 years ago

GEOMETRY!!!! K' (6,5) is the image of K after a reflection in the line y=2. what are the coordinates of K

frutty [35]

Given:

The coordinates of point K' are (6,5).

K' is the image of K after a reflection in the line y=2.

To find:

The coordinates of point K.

Solution:

Let the coordinates of point K are (a,b).

If a figure is reflected over the line y=2, then

$(x,y)\to (x,2(2)-y)$

$(x,y)\to (x,4-y)$

Using this formula, the coordinates of image of K are

$K(a,b)\to K'(a,4-b)$

The coordinates of point K' are (6,5).

$K'(a,4-b)=K'(6,5)$

On comparing both sides, we get

$a=6\text{ and }4-b=5$

$a=6\text{ and }-b=5-4$

$a=6\text{ and }-b=1$

$a=6\text{ and }b=-1$

Therefore, the coordinates of point K are (6,-1).

3 0

2 years ago