Complete question :
Suppose someone gives you 8 to 2 odds that you cannot roll two even numbers with the roll of two fair dice. This means you win $8 if you succeed and you lose $2 if you fail. What is the expected value of this game to you? What can you expect if you play 100 times.
Answer:
$0.5 ; win $50 with 100 rolls
Step-by-step explanation:
From a roll of two fair dice; probability of obtaining an even number :
Even numbers = (2, 4, 6) = 3
P = 3 /6 = 1 /2
For 2 fair dice ; probability of rolling two even numbers : independent event.
1/2 * 1/2 = 1/4
Hence, p(success) = 1/4 ; P(failure) = 1 - 1/4 = 3/4
Probability table
Winning = $8 or loss = - $2
X : ____ 8 ______ - 2
P(x) __ 1/4 ______ 3/4
Expected value : E(x) = ΣX*P(x)
E(x) = (8 * 1/4) + (-2 * 3/4)
E(x) = 2 - 1.5
E(x) = $0.5
Since expected value is positive, the expect to win
If played 100 times;
Expected value = 100 * $0.5 = $50
Yes it’s means multiplication.
Let start off with 5/8+7/8= 1 4/8
Now it's 13+1 4/8= 14 4/8 or 14 1/2 :)
Answer:
yes
Step-by-step explanation:
I think you did the question correctly. good luck
Answer:
C.y = 3x + 4
Step-by-step explanation:
We have two points, so we can find the slope
m = (y2-y1)/ (x2-x1)
= (7--2)/ (1--2)
= (7+2)/(1+2)
= 9/3
=3
The slope is 3
We can find the point slope form of the line
y-y1 = m(x-x1)
y-7 = 3(x-1)
Distribute
y-7 =3x-3
Add 7 to each side
y-7+7 = 3x-3+7
y = 3x+4
This is in slope intercept form (y=mx+b)
