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mixas84 [53]
3 years ago
14

Without drawing the graph of the function y=1.2x−7, see if the graph passes through points: ( 300; 353)

Mathematics
1 answer:
artcher [175]3 years ago
3 0

Answer:

( 300; 353) is on the line y=1.2x−7

Step-by-step explanation:

y=1.2x−7

Substitute the point into the equation and see if it is true

353=1.2(300)−7

353 =360-7

353 = 353

This point is on the line

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What is the value of c in the equation y = 4x^2 -10x + c if the y-coordinate of the vertex is -7
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Answer: c=-\frac{3}{4}

Step-by-step explanation:

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Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

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