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VMariaS [17]
3 years ago
12

Why I don't have information to find the missing lengths? ​

Mathematics
2 answers:
balandron [24]3 years ago
5 0
Ask your teacher. Or is that what you need answered
OverLord2011 [107]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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When the sum of 1.9 and 2.2 is subtracted from the product of 1.9 and 2.2, what is the difference?
Nitella [24]
OK the question is asking what happens when you subtract (1.9+2.2) from 1.9x2.2 or more clearly 1.9x2.2-(1.9+2.2) which equals 4.18-4.1 or .08
5 0
4 years ago
Maths easy class 8 whoever gets it I will give u brainlist​
asambeis [7]

Answer:

424 cm²

Step-by-step explanation:

The figure is composed of a square and a trapezium on top

A of square = 18² = 324 cm²

A of trapezium = \frac{1}{2} h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 8, b₁ = 18 and b₂ = 7 , then

A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²

Area of hexagonal park = 324 + 100 = 424 cm²

8 0
3 years ago
How many answers does –2(3x – 1) = –6x – 1 have
GaryK [48]

Answer:

it has 3 steps

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
What should be avoided when writing a summary? Select the two correct answers.
Olin [163]

Answer:

plagiarizer, and option

Step-by-step explanation:

3 0
3 years ago
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A Bernoulli differential equation is one of the form dxdy+P(x)y=Q(x)yn Observe that, if n=0 or 1, the Bernoulli equation is line
aleksandr82 [10.1K]

It's unclear whether the ODE is

xy'+y=4xy^2

or

xy+y'=4xy^2

If the first case, then divide through both sides by y^2 to get

xy^{-2}y'+y^{-1}=4x

then substitute z=y^{-1}, so that z'=-y^{-2}y'. Then

-xz'+z=4x\implies-\dfrac1xz'+\dfrac1{x^2}z=\left(-\dfrac1xz\right)'=\dfrac4x

\implies-\dfrac1xz=\displaystyle\int\frac4x\,\mathrm dx

\implies z=-4x\ln|x|+Cx

\implies\boxed{y=\dfrac1{Cx-4x\ln|x|}}

If the second, then dividing through by y^2 gives

xy^{-1}+y^{-2}y'=4x

The same substitution as before gives

xz-z'=4x\implies e^{-x^2/2}z'-xe^{-x^2/2}z=\left(e^{-x^2/2}z\right)'=-4xe^{-x^2/2}

\implies e^{-x^2/2}z=\displaystyle-4\int xe^{-x^2/2}\,\mathrm dx

\implies z=4+Ce^{x^2/2}

\implies\boxed{y=\dfrac1{4+Ce^{x^2/2}}}

5 0
3 years ago
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