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3 years ago

I need to solve for a and b

Mathematics

1 answer:

Jlenok [28]3 years ago

5 0

Answer:

Not sure Sorry i couldn't help

Step-by-step explanation:

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Lauren has 108 pieces of candy leftover from Halloween. She would like to distribute them evenly to the 9 kids on her block. Wri

Pani-rosa [81]

Answer:

each kid gets 9 pieces

Step-by-step explanation:

5 0

3 years ago

-3 (2m+5)+8=5 (-2m+1)

Zanzabum

I just worked out the problem twice and got -4.5 both times.

3 0

4 years ago

Read 2 more answers

Let z =38 (cos(pi/8)+ i sin(pi/8)) and w = 2 (cos( pi/16 ) + i sin(pi/16))

mario62 [17]

Answer:

$zw=76 * (cos(\frac{3\pi}{16}) +isin(\frac{3\pi}{16}) )$

Step-by-step explanation:

Given

$z =38 (cos(\frac{\pi}{8})+ i sin(\frac{\pi}{8})$ and

$w = 2 (cos(\frac{\pi}{16} ) + i sin(\frac{\pi}{16})$

Required

Determine zw

Given that:

$x = v_1(cos(a) + isin(a))$ and $y = v_2(cos(b) + isin(b))$

$x * y = (v_1 * v_2)*((cos(a+b) + isin(a+b))$

So, we have:

$zw=(38 * 2) * (cos(\frac{\pi}{8} + \frac{\pi}{16}) + isin(\frac{\pi}{8} + \frac{\pi}{16}))$

$zw=76 * (cos(\frac{2\pi + \pi}{16})+isin(\frac{2\pi + \pi}{16}))$

$zw=76 * (cos(\frac{3\pi}{16}) +isin(\frac{3\pi}{16}) )$

7 0

3 years ago

a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.

ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: $\mathbf{Length = a -5}$ and $\mathbf{Width = a^2 + 5a + 25}$

The area is given as:

$\mathbf{Area = a^3 - 125}$

Express 125 as 5^3

$\mathbf{Area = a^3 - 5^3}$

Apply difference of cubes

$\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}$

$\mathbf{Area = (a - 5)(a^2 + 5a + 25)}$

The area of a rectangle is:

$\mathbf{Area = Length \times Width}$

So, by comparison:

$\mathbf{Length = a -5}$

$\mathbf{Width = a^2 + 5a + 25}$