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3 years ago

Withint on the number line would apresent -2 1/4 HELP MEEEE PLSSS

Mathematics

1 answer:

DochEvi [55]3 years ago

5 0

Answer:

<em>Answer B</em>

Step-by-step explanation:

<u>Fractions on the Number Line</u>

The number line contains an ordered sequence of the numbers, where the smaller numbers are at the left of the greater numbers.

This means -3 is to the left of -2, which is to the left of -1.

Number -2 1/4 lies between -2 and -3.

The only point lying on that interval is B.

Answer B

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Answer:

$\sqrt{697}$

Step-by-step explanation:

If the base of the square pyramid has an area of 576 units, then the side length must have a length of $\sqrt{576}=24$ . 24/2=12, and using the pythagorean theorem you can find that the height of the pyramid is $\sqrt{29^2-12^2}=\sqrt{697}$ . Hope this helps!

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3 years ago

Joey runs diagonally across a rectangular field. The field had a width of 15 yards and a length of 36 yards. How far did Joey ru

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Answer:

Joey ran 39 yards

Step-by-step explanation:

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3 years ago

A factory produces c cans of paint in h hours according to the equation c= 50h. What represents the unit rate of cans produced p

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50 cans are made per hour

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3 years ago

Determine whether the following points are a solution to the given system.

Alika [10]

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5 0

3 years ago

Line segment DB and line segment AE are medians. If BC=6y+10, AB=22+3y, CE=6x+12, ED=2x+60, then find the value of x and y, and

garri49 [273]

Answer:

$x=45.5,\ y=\dfrac{280}{3}.$

Step-by-step explanation:

Line segment DB and line segment AE are medians, then

$AD=DC=\dfrac{1}{2}AC;$
$BE=CE=\dfrac{1}{2}BC.$ .

This gives you that $6x+12=\dfrac{6y+10}{2}.$

By the triangle midline theorem,

$DE=\dfrac{1}{2}BC,$

then

$2x+60=\dfrac{22+3y}{2}.$

Solve the system of two equations:

$\left\{\begin{array}{l}6x+12=\dfrac{6y+10}{2}\\ \\2x+60=\dfrac{22+3y}{2}\end{array}\right.\Rightarrow \left\{\begin{array}{l}12x+24=6y+10\\ \\4x+120=22+3y\end{array}\right.\Rightarrow \left\{\begin{array}{l}6x-3y+7=0\\ \\4x-3y+98=0\end{array}\right.$

Subtract the second equation from the first one:

$6x-3y+7-(4x-3y+98)=0,\\ \\2x=98-7,\\ \\2x=91,\\ \\x=45.5.$

Then

$4\cdot 45.5-3y+98=0,\\ \\3y=280,\\ \\y=\dfrac{280}{3}.$

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3 years ago