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Andrei [34K]
3 years ago
13

Find the product of 2x 3 xy and 5​

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

30x²y

Step-by-step explanation:

2x × 3xy × 5

= 2 × 3 × 5 × x × xy

= 30x²y

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Equivalent expressions for 7x-6x+4x
Alekssandra [29.7K]

Answer:

<h3>5x</h3>

Step-by-step explanation:

7x-6x+4x ← <em>(Add and subtract elements to the numbers from left to right.)</em>

<em />

7-6+4

PEMDAS- (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) from left to right.

7-6+4 ← (Add & subtract.)

7-6=1

1+4=5

= 5x

5x, which is our answer.

5 0
3 years ago
Ive been waiting hours for someone to answer this question. Is everyone an idiot.
stepan [7]

Answer:

D) x = -2/3 and x = 6

Step-by-step explanation:

4(x²−x+2)−(x+10)(x+2)           Distribute

(4)(x²) + (4)(−x) + (4)(2) + − x² + −12x + −20    Multiply

4x² + −4x + 8 + −x² + −12x + −20           Combine like terms            

(4x² + −x²) + (−4x + −12x) + (8 + −20)      Combine like terms

3x² −16x −12 = 0      

x = -2/3 and x = 6

I graphed the equation on the graph below.

If this answer is correct, please make me Brainliest!

7 0
3 years ago
I have a radius of 35ft, what is the diameter ?
lianna [129]

Answer:

r=35ft, d=70ft. when r=15 mm, d=30mm

Step-by-step explanation:

Radius is half of diameter

3 0
3 years ago
Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

and

\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

3 0
3 years ago
Read 2 more answers
A teacher surveys 30 students on the the number of books they read over the summer.The data are represented in the box plot what
Margaret [11]

Answer:

Wheres the plot?

Step-by-step explanation:

8 0
3 years ago
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