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Lorico [155]
2 years ago
11

Which sentence can represent the inequality 3.5x>7?

Mathematics
2 answers:
Andrei [34K]2 years ago
3 0

Answer:A

Step-by-step explanation:hole this helps

serg [7]2 years ago
3 0

Answer:

C) The product of 3.5 and a number is greater than 7

Step-by-step explanation:

did edge 2020

mark as brainliest plz

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What is the volume of a cube that measures 5 cm on each side?
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 V = a ^ 3

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5 0
3 years ago
PLEASE HELP I DONT UNDERSTAND!!
slega [8]

Answer:

see explanation

Step-by-step explanation:

3x and 144 are adjacent angles on a straight line and sum to 180°

3x + 144 = 180 ( subtract 144 from both sides )

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divide both sides by 3

x = 12

and

2y - 5 and 95 are vertically opposite angles and are congruent, so

2y - 5 = 95 ← value of 2y - 5

add 5 to both sides

2y = 100 ( divide both sides by 2 )

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Then

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7 0
2 years ago
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8_murik_8 [283]

Answer:

3 hours

Step-by-step explanation:

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3 0
3 years ago
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Match the verbal description to the correct expression.
dusya [7]

Answer:

1.    n + 34

2.   n - 34

3.   n × 34

Step-by-step explanation:

1. 34 more than a number     n + 34

2. a number decreased by 34      n - 34

3. the product of a number and 34    n × 34

6 0
2 years ago
Andrea calls two truck rental companies to compare costs. Action trucks charges $80 for the day plus $0.22 per kilometer and tru
Amanda [17]

Answer:it will take 200 kilometers for the costs to be the same.

Step-by-step explanation:

Let x represent the number of kilometers that Andrea would have to drive for the total cost of renting from both companies to be the same.

Action trucks charges $80 for the day plus $0.22 per kilometer. It means that the total cost of x miles would be

80 + 0.22x - - - - - - - - - 1

Truck experts charges $100 for the day plus $0.12 per kilometer. It means that the total cost of x miles would be

100 + 0.12x - - - - - - - - - 2

Therefore, for the cost of renting from both companies to be the same,

80 + 0.22x = 100 + 0.12x

0.22x - 0.12x = 100 - 80

0.1x = 20

x = 20/0.1 = 200

4 0
3 years ago
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