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spin [16.1K]
3 years ago
7

Pleas help me fast!

Mathematics
2 answers:
Lunna [17]3 years ago
4 0

Answer:

35

Step-by-step explanation:

17-7+5^2  Divide 28 by 4

17-7+25  5 to the power 2 is 25

10+25     add 25 and 10 and you get 35.

35

neonofarm [45]3 years ago
4 0

Answer:

35

Step-by-step explanation:

You might be interested in
What is the solution to this system of equations? 4x + 5y = 7
Nutka1998 [239]

Answer:

(-2, 3)

Step-by-step explanation:

4x + 5y = 7

3x - 2y = -12

Let's solve this by elimination. We want to eliminate one variable at a time. This means we need to multiply the equations to create a common multiple to cancel out a variable.

Let's work with y.

5y and -2y: For these values to cancel out, we need to multiply each term to create a common multiple.

2(4x + 5y = 7)

5(3x - 2y = -12)

Multiply.

8x + 10y = 14

15x - 10y = -60

Eliminate.

23x = -46

Divide both sides by 23.

x = -2

Now that we know x, let's plug it back into one of equations to find y.

4x + 5y = 7

4(-2) + 5y = 7

Multiply.

-8 + 5y = 7

Add.

5y = 15

Divide.

y = 3

Now we know x and y; let's plug both back into the equation we have not checked yet.

3x - 2y = -12

3(-2) - 2(3) = -12

Multiply.

-6 - 6 = -12

Subtract.

-12 = -12

Your solution is correct.

(-2, 3)

Hope this helps!

8 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
10 POINTS!!!
Citrus2011 [14]

pr=no:of favourable outcomes/no:of possible outcomes

no:of favourable outcomes=1

no:of possible outcomes=

c^{20_{3} =20/3(20-3)=\\17*18*19*20/2*3*17=\\18*19*20/6\\=3*19*20\\=1140\\therefore,\\pr=1/1140

8 0
4 years ago
HELP!!BRAINLIEST!!<br> 9. Identify the congruent triangles in the figure.
LenKa [72]
<h3>Answer: Choice A) triangle FDE = triangle IGH</h3>

There are 3 ways to label any triangle. We simply list 3 points in any order. Once we pick an order, the other triangle must follow that same pattern for the sides and angles to match up.

With choice A, we start at the bottom for both triangles (points F and I). For the triangle on the right, we go in counterclockwise direction to get F, D, then E. So we have FDE. The triangle on the left will go opposite this and we go clockwise: I to G to H. So we have IGH.

angle F = angle I

angle D = angle G

angle E = angle H

segment FD = segment IG

segment DE = segment GH

segment EF = segment GI

3 0
3 years ago
(1+5/6)(1-5/6)<br><br> I don't understand it
ipn [44]
(a+b)(a-b) = a^2 - b^2

(1+5/6) (1-5/6) = 1^2 - (5/6)^2 = 1 - 25/36 = 36/36 - 25/36 = (36-25)/36 = 11/36

11/36 is your answer
5 0
4 years ago
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