All categories

3 years ago

Simplify each expression 1. 5 + 3 (x - 5) + 7 2. 1/2+2/3(y- 6)

Mathematics

2 answers:

exis [7]3 years ago

8 0

Answer:

3(x-1)

Step-by-step explanation:

12+3x-15

-3+3x

3(x-1)

kirza4 [7]3 years ago

8 0

I agree with the top comment
3(x-1)

You might be interested in

Last year, lien earned 1200 more than her husband. Together they earned 45,200. How much did each of them earn?

nasty-shy [4]

Husband earned 22,600
lien earns 23,800

8 0

2 years ago

Use the data set shown below to complete the sentence 3,3,4,5,5,9 the mean the median

lorasvet [3.4K]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ Mean = 4.8 Median = 4.5

The mean is the average. To find the mean add up all the numbers and divide by the number of numbers:

3 + 3 + 4 + 5 + 5 + 9 = 29

29 ÷ 6 = 4.8

To find the mean, keep crossing out numbers until you are left with one number (for an odd amount of numbers). When you have an even amount of numbers, keep crossing out until you are left with 2 numbers. Add those 2 numbers and then divide:

4 + 5 = 9

9 ÷ 2 = 4.5

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

6 0

3 years ago

Read 2 more answers

Plz help this is due today NO LINKS OR GROSS PICTURES OR I Will REPORT And please show work

pychu [463]

Answer: Trapezoid

Step-by-step explanation:

Trapezoids are parollelograms, that’s all

6 0

3 years ago

The sum of the measures of the interior angles of a polygon with n sides is

Andrew [12]

Answer:

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = (n - 2) × 180° ← n is the number of sides

8 0

3 years ago

What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*

pickupchik [31]

<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation $x^4-41x^2=-400$ .

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

$x^4-41x^2+400=-400+400$ .

$x^4-41x^2+400=0$ .

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

$x^4-25x^2-16x^2+400=0$

Making it into two groups, we get

$(x^4-25x^2)+(-16x^2+400)=0$

Factoring out GCF of each group, we get

$x^2(x^2-25)-16(x^2-25)=0$

$(x^2-25)(x^2-16) =0$

Factoring out $(x^2-25)$ and $(x^2-16)$ separately by difference of the squares identity $a^2-b^2=(a-b)(a+b)$ , we get

$(x^2-25) = x^2-5^2= (x-5)(x+5)$ and

$x^2-16 = x^2-4^2 =(x-4)(x+4)$ .

Therefore,

$(x-5)(x+5)(x-4)(x+4) =0$

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

6 0

3 years ago