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gtnhenbr [62]
3 years ago
15

Someone, please answer this.

Computers and Technology
1 answer:
Sav [38]3 years ago
7 0

Answer: A loop will continue running until the defined condition returns false . ... You can type js for , js while or js do while to get more info on any of these. ... initialization - Run before the first execution on the loop. ... But it can be used to decrement a counter too. statement - Code to be repeated in the loop.

Explanation:

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Try to crack the code:
ololo11 [35]

Answer:001101110010010100011011010110010011100100100000001100100100110001000010001101100100010100100000001101100100100001010001010101001101001010

Explanation:

i copied

3 0
3 years ago
eocs can be fixed locations, temporary facilities, or virtual structures with staff participating remotely.
levacccp [35]

EOCS can be fixed locations, temporary facilities, or virtual structures with staff participating remotely is a true statement.

<h3>What is the Emergency Operations Centers (EOC)?</h3>

Emergency Operations Centers is known to be part of the four NIMS Command and Coordination structures as the EOCs are known to be used  in an off site locations where staff are gotten from a lot of agencies that come together to address some imminent kind of threats and hazards.

Therefore saying that EOCS can be fixed locations, temporary facilities, or virtual structures with staff participating remotely is a true statement.

Learn more about EOCS from

brainly.com/question/10794095

#SPJ1

5 0
2 years ago
Write a program that uses nested loop or for statements to display Pattern A below, followed by an empty line and then another s
JulsSmile [24]

Answer:

public class Pyramid {

   public static void main(String[] args) {

             int h = 7;

       System.out.println("Pattern A");

               for(int i = 1; i <= h; ++i)

               {

                   for(int j = 1; j <= i; ++j) {

                       System.out.print("+");

                   }

                   System.out.println();

               }

       System.out.println();

       System.out.println("Pattern B");

               for (int i = 1; i<=h; ++i)

               {

                 for(int j = h; j >=i; --j){

                     System.out.print("+");

                 }

                   System.out.println();

               }

           }

       }

Explanation:

  • The trick in this code is using a nested for loop
  • The outer for loop runs from i = 0 to the heigth of the triangle (in this case 7)
  • The inner for loop which prints the (+) sign runs from j = 0 to j<=i
  • It prints the + using the print() function and not println()
  • In the pattern B the loop is reversed to start from  i = height
8 0
3 years ago
When you are almost done with your soup and want to get at the last little bit, how should you do this 2
pav-90 [236]

Answer:

<u>B. Tip the bowl slightly, then spoon up the last bit</u>

Explanation:

Generally speaking none of the other answers made much of sense.. "tip the bowl from side to side" doesn't help you at all, neither does "Keep spooning as much as you can, then stop eating". Neither of these will help you spoon up the last little bit, <u>the most logical answer is B. "Tip the bowl slightly, then spoon up the last bit"</u>. If this is not the correct answer then it'd be D, but I don't believe/feel that it's "poor etiquette" to "leave the last little bit".

7 0
3 years ago
The Zootopia Police Department is recruiting new officers and has come up with an innovative equation to hire. They define hireS
Dahasolnce [82]

Answer:

#include<iostream>

#include<limits>

#include<iomanip>

using namespace std;

//function that returns true

//if there is invalid input like giving string as input

// for integer value.

bool isInvalidInput()

{

  //return true if cin.fail

  if(cin.fail())

  {

      //clear the buffer

      cin.clear();

      cin.ignore(numeric_limits<streamsize>::max(),'\n');

      return true;

  }

  return false;

}

//function that calculates the hire score for given 3 parameters.

double calHireScore(double agility,double strength,double speed)

{

  return (1.8*agility) + (2.16 * strength) + (3.24 * speed);

}

//calculate hire score for fox.

void calFoxHireScore()

{

  double agility,strength;

 

  cout<<"Enter Agility Value: ";

  //get agility as input and validate it.

  cin >> agility;

  if(isInvalidInput() || agility <= 0)

  {

      cout<<"\nError: Agility value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Strength Value: ";

  cin >> strength;

  if(isInvalidInput() || strength <= 0)

  {

      cout<<"\nError: Strength value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Fox: "<<calHireScore(agility,strength,0)<<endl;

}

//function that asks input from user for

//calculating hire score for Sloth.

void calSlothHireScore()

{

  double strength,speed;

 

  cout<<"Enter Strength Value: ";

  cin >> strength;

  if(isInvalidInput() || strength <= 0)

  {

      cout<<"\nError: Strength value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Speed Value: ";

  cin >> speed;

  if(isInvalidInput() || speed <= 0)

  {

      cout<<"\nError: Speed value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Sloth: "<<calHireScore(0,strength,speed)<<endl;

}

//function that asks input from user for

//calculating hire score for Bunny.

void calBunnyHireScore()

{

  double agility,speed;

 

  cout<<"Enter Agility Value: ";

  cin >> agility;

  if(isInvalidInput() || agility <= 0)

  {

      cout<<"\nError: Agility value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Speed Value: ";

  cin >> speed;

  if(isInvalidInput() || speed <= 0)

  {

      cout<<"\nError: Speed value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Bunny: "<<calHireScore(agility,0,speed)<<endl;

}

//function to display menu for user.

void menu()

{

  cout<<"\n1. Fox"<<endl;

  cout<<"2. Bunny"<<endl;

  cout<<"3. Sloth"<<endl;

  cout<<"0. Quit"<<endl;

  cout<<"Enter your choice: ";

}

//main method

int main()

{

  int choice;

  do

  {

      //asks choice

      menu();

      cin >> choice;

      //if invalid input print erro message

      if(isInvalidInput())

      {

          cout<<"\nError: Invalid choice enetered. Try Again\n";

      }

      else

      {

          cout<<"\n";

          //if any one of the choices do accordingly

          //for invalid choice print error mesage.

          switch(choice)

          {

              case 1:

                  calFoxHireScore();

                  break;

              case 2:

                  calBunnyHireScore();

                  break;

              case 3:

                  calSlothHireScore();

                  break;

              case 0:

                  cout<<"\nQutting...\n";

                  break;

              default:

                  cout<<"Invalid choice entered."<<endl;

                  break;

          }

      }

     

  }while(choice != 0);

 

  return 0;

}

Explanation:

3 0
4 years ago
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