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Olenka [21]
3 years ago
9

Is 3 inches on a map covers 225 miles what is the scale on inches 2 miles

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:24

Step-by-step explanation:2 devided by 225 is 75 so 75 devided by 3 is 24

tell me if im wrong

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Find the midpoint of a segment whose endpoints are (-9,5) and (5,-1).
iVinArrow [24]
The answer is B (-2,2)
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4 years ago
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When evaluating (3.25 times 10 Superscript 5 Baseline) (1.82 times 10 Superscript 3 Baseline), what will be the exponent of 10 i
boyakko [2]

Answer:

The exponent of 10 in the product is 8.

Step-by-step explanation:

The expression is as follows:

(3.25\times 10^{5})\cdot (1.82\times 10^{3})

Exponent rule:

a^{m}\times a^{n}=a^{m+n}

Simplify the expression as follows:

(3.25\times 10^{5})\cdot (1.82\times 10^{3})=3.25\times 10^{5}\times 1.82\times 10^{3}

                                        =(3.25\times 1.82)\times (10^{5}\times 10^{3})\\\\=5.915\times 10^{5+3}\\\\=5.915\times 10^{8}

Thus, the exponent of 10 in the product is 8.

3 0
3 years ago
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Please help Solve:(<br> 15-3x=3
olchik [2.2K]

Hi!

Answer:

\boxed{X=4}

Step-by-step explanation:

You subtract by 15 both sides of an equation.

15-3x-15=3-15

Simplify equation.

-3x=-12

Then, you divide by -3 both sides of an equation.

\frac{-3x}{-3}=\frac{-12}{-3}

Simplify.

12/3=4

\boxed{X=4}, which is our final answer.

Hope this helps!

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valentina_108 [34]

Answer: The correct option is tan(F).

Explanation:

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It is also given that DE=EF=5 and DF=5\sqrt{2}.

Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.

\cos (F)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(F) is \frac{1}{\sqrt{2}}.

\sin (F)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(F) is \frac{1}{\sqrt{2}}.

\sin (D)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(D) is \frac{1}{\sqrt{2}}.

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The value of tan(F) is 1. Which is not equal to \frac{1}{\sqrt{2}}.

\cos (D)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(D) is \frac{1}{\sqrt{2}}.

Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.

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Answer:

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Step-by-step explanation:

4 0
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