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3 years ago

(SAT PREP) Find the value of x. (I have several, please help!!)

Mathematics

1 answer:

balandron [24]3 years ago

7 0

question 1 :- sum of all angles of a triangle is 180°

so, x + 39° + 25° + 15° = 180°

⇒x + 79° = 180°

⇒x = 101°

question 2 : draw the along with AD and make and triangle as shown in figure.

as ABCD is a parallelogram. so, angle FDE = 180° - x

and angle FED = 180° - x [ as FEA + FED = 180° ]

now from ∆DEF,

50° + 180° - x + 180° - x = 180°

⇒230° - 2x = 0

⇒x = 105°

also read : If (A + B) =(A-B) then the angle between the Ả and B.

brainly.in/question/12391097

(SAT Prep) In the figure, a+b+d+e =

A. 330°

B. 325°

C. 290°

D. 300°

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3 years ago

I WILL GIVE YOU 40 POINTS AND THE HIGHEST ANSWER. YOU HAVE TO DO WHAT THE STEPS SAYS IN ORDER TO GET EVERYTHING

Marat540 [252]

This is a 30-60-90 triangle, in which the side opposite of the 90 degrees is the longest side (2), the side opposite of the 60 degrees is the √3 (2√3 in this case), and the last side (opposite of the 30 degrees) is the (1)

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3 years ago

A person standing in the ground throws a ball onto a flat rooftop. The ball rolls around for several seconds. Then the ball fall

natali 33 [55]

Answer:

Graph D

Step-by-step explanation:

According to the question, the correct graph is D.

It's not A because, the ball is thrown after some pause and the ball doesn't roll on the roof, falls immediately.

It's not B or C because the ball goes up after reaching the roof but should fall down.

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2 years ago

The mean height of married American women in their early twenties is 64.5 inches and the standard deviation is 2.5 inches. The m

SSSSS [86.1K]

Answer:

The equation for regression line and predicting a husband's height for married couples in their early 20s

Equation: Y'=33.67+0.54*X'

Step-by-step explanation:

r=0.5

x'=64.5

Sx=2.5

y'=68.5

Sy=2.7

General regression line equation is:

Y'=a+b*X'

so the slope of the regression line is the linear correlation coefficient multiplied by the standard deviation for y' divided by the standard deviation for x'

$b=r*\frac{S_{y}}{S_{x}}\\b=0.5*\frac{2.7}{2.5}\\b=0.54$