question 1 :- sum of all angles of a triangle is 180°
so, x + 39° + 25° + 15° = 180°
⇒x + 79° = 180°
⇒x = 101°
question 2 : draw the along with AD and make and triangle as shown in figure.
as ABCD is a parallelogram. so, angle FDE = 180° - x
and angle FED = 180° - x [ as FEA + FED = 180° ]
now from ∆DEF,
50° + 180° - x + 180° - x = 180°
⇒230° - 2x = 0
⇒x = 105°
also read : If (A + B) =(A-B) then the angle between the Ả and B.
brainly.in/question/12391097
(SAT Prep) In the figure, a+b+d+e =
A. 330°
B. 325°
C. 290°
D. 300°
