You were given the data as statistics so that you can predict the number of a certain type of fish through ratio and proportion. The main focus here is then number of bluegill fish. From the given statistics, the number is 87. The total number of fishes at that time was 52+61+87 = 200. So, assuming that this composition is uniform in the said lake. We can then use the ratio from the given statistics to know the proportion of bluegills to the total fishes. Hence, we equate the two ratios:
87/200 = x/800
where x is the number of bluegills among the 800 total fishes that is in proportion to the gathered statistics. Solving for x, we determine the answer to be
x = 348
Step-by-step explanation:


And



So
∈ ![(6, 9]](https://tex.z-dn.net/?f=%286%2C%209%5D)
Please give me a brainliest answer
The given table is an example of constant exponential decay.
It is given that
X Y
-4 16
-1 2
2 0.25
4 0.0625
5 0.03125
<h3>What is an exponential function?</h3>
An exponential function is a relation of the form y = a^x, with the independent variable x ranging over the entire real number line as the exponent of a positive number a.
The y-value at -4 is 16 while the y-value at -1 is 2, a decrement of 1/8 times for an increment in x-value by 3
Again, the y-value at 2 is 0.25 while the y-value at 5 is 0.03125, a decrement of 1/8 times for an increment in x-value by 3.
In both cases, the rate of decrement is constant.
So we can say that this is an example of constant exponential decay.
We can also see this behavior from the attached graph.
Therefore, the given table is an example of constant exponential decay.
To get more about exponential function visit:
brainly.com/question/11464095
Answer:
Step-by-step explanation:
Alright, lets get started.
In the morning Cynthia completed the work = 
During her lunch break, she completed = 
So, she completed total of her work : 
So, we need to add these two fractions.
First making common denominator , so

So, adding = 
It means she had finished
fraction of het to do list. : Answer
Hope it will help :)