Answer:
a b c
plz give branliest
Step-by-step explanation:
The answer for this problem is 16
Answer:
Do the data from this shipment indicate statistical control: No
Step-by-step explanation:
Calculating the mean of the sample, we have;
Mean (x-bar) = sum of individual sample/number of sample
= (0+0+0+0.004+0.008+0.020+0.004+0+0+0.008)/10
= 0.044/10
= 0.0044
Calculating the lower control limit (LCL) using the formula;
LCL= (x-bar) - 3*√(x-bar(1-x-bar))/n
= 0.0044 - 3*√(0.0044(1-0.0044))
= 0.0044- (3*0.0042)
= 0.0044 - 0.01256
= -0.00816 ∠ 0
Calculating the upper control limit (UCL) using the formula;
UCL = (x-bar) + 3*√(x-bar(1-x-bar))/n
= 0.0044 + 3*√(0.0044(1-0.0044))
= 0.0044+ (3*0.0042)
= 0.0044 + 0.01256
=0.01696∠ 0
Do the data from this shipment indicate statistical control: No
Since the value 0.02 from the 6th shipment is greater than the upper control limit (0.01696), we can conclude that the data from this shipment do not indicate statistical control.
Would this be the correct answer? If not, can you further explain the question?(11x+8y)(11x-8y)
Answer:
x=45/6
Step-by-step explanation:
2+7y=8. 7y=8-2. <u>7</u><u>y</u><u>=</u><u>6</u>
7=7. y=6\7
insert the value of y in the second equation. 5x-7y=16
5x-7(6/7)=16
5x-49\6=16
collect the liketerms together
5x=16+49/6
5x=145/6(divide both sides by 5)
x=29/6
x=45/6
<em><u>f</u></em><em><u>u</u></em><em><u>r</u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u>r</u></em><em><u>.</u></em>
<em><u> </u></em>confirm if the 2 in the second equation has an X coz the questions are normally set with both equations having both values x and y
