The fare of $(20 - 2.5) = $17.5 will maximize the total fare.
<h3>What is Differentiation?</h3>
Differentiation means the rate of change of one quantity with respect to another. The speed is calculated as the rate of change of distance with respect to time.
Here, The operator for a round-trip fare of $20, carries an average of 500 people per day.
It is estimated that 20 fewer people will take the trip, for each $1 increase in fare.
for $x increase in fare, 20x less people will take the trip and at that time the total fare F is given by
f(x) =(20 + x)(500 - 20x)
f (x) = 10000 + 100x - 20x²
For f(x) to be maximum, the condition is dy/dx = 0
100 - 40x = 0
⇒ x = 2.5
Thus, the fare of $(20 - 2.5) = $17.5 will maximize the total fare.
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Answer:
The distance the Bensons had traveled from their home 
hours after picking up their grand parents 292.5 miles
Step-by-step explanation:
The given equation for the distance the Benson family traveled from their home can be presented as follows;
d = 55·t + 100
Where;
d = The total distance that the Benson family has traveled from their home after traveling 100 miles to pick up their grandparents
t = The time duration the Benson family have been traveled from their grandparents home on the way to their vacation
To find how far from their home the Bensons will be after 3 1/2 hours of driving with their grand parents, we substitute t with 3 1/2 hours or 3.5 hours as follows;
d = 55·t + 100
When t = hours, we get;
Therefore, the distance the Bensons had traveled from their home hours after picking up their grand parents = 292.5 miles.
Answer:
51.3
Step-by-step explanation:
There are two ways you can do this. You can use the longer way:
15+16+17+18+19+20+21+22+23+24 = 195 (starting from the top row, which has 15 logs, up until the bottom row, which has 24 logs, on condition that each second row has one log more than the previous one)
You can also use the formula (where n is the number of rows)
x= (n(first term+last term))/2
x= (10(15+24))/2
x= (10*39)/2
x=390/2
x=195
Either way, there are 195 logs in the stack.
