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3 years ago

HOWEVER ANSWERS CORRECTLY I'LL GIVE BRAINLIEST!!!!!!!!!!!!!!

Mathematics

1 answer:

Verdich [7]3 years ago

5 0

Answer:

6^6

Step-by-step explanation:

The exponents are subtracted when in this form, but whole number stays the same. Trust me on this one, these are wayy too easy

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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary). 2,6, 18,... Find the 8th term.

Andrei [34K]

Answer:

4,374

Explanation:

Given the sequence: 2, 6, 18, ...

If we study the pattern we observe that:

$\begin{gathered} \frac{6}{2}=3 \\ \frac{18}{6}=3 \end{gathered}$

This is a geometric sequence with:

• The first term, a=2

• Common Ratio, r=3

The nth term of a geometric sequence is obtained using the formula:

$U_n=ar^{n-1}$

Therefore, the 8th term will be:

$\begin{gathered} U_8=2\times3^{8-1} \\ =2\times3^7 \\ =4374 \end{gathered}$

The 8th term of the sequence is 4,374.

4 0

2 years ago

what is the factorization of the trinomial below -x^2+x+42 A. (x+6)(x-7) B. -1(x+7)(x+6)C. -1(x-7)(x+6) D. (-x+6)(x+7)

IRISSAK [1]

Answer:

-(x - 7)(x + 6)

Step-by-step explanation:

Step 1: Factor GCF

-1(x² - x - 42)

Step 2: Factor quadratic

-1(x - 7)(x + 6)

5 0

3 years ago

Read 2 more answers

Please help ASAP Gavin works as a salesperson at an electronics store and sells phones and phone accessories. Gavin earns a $12

andreev551 [17]

Answer:

6 phones and 18 accessories

Step-by-step explanation:

12P + 3.50A = 135

A = 12 + P

12P + 3.50(12 + P) = 135,

12P + 42 +3.50P = 135

15.50P = 93

P = 6 phones

A = 12 + 6 = 18 accessories

4 0

3 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

3 years ago

2x-3x=<br> Pls I don’t understand

Akimi4 [234]

Answer:

-1x

explanation:

2-3= -1

sorry if this is wrong.

6 0

3 years ago