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DENIUS [597]
3 years ago
7

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Computers and Technology
2 answers:
forsale [732]3 years ago
8 0

Answer: B

Explanation:

kykrilka [37]3 years ago
7 0

Answer:

Its B                                                                                                                                            

Explanation:

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class Login: def __init__(self): self.login_name = 'none' self.login_password = 'none' # TODO: Define class method - check_crede
Gnoma [55]

Create boolean variable that receives return value from # calling check_credentials(login, password) # TODO a loop that will continue until login attempts run out or a successful login is returned # TODO #elegance Login elegance Login: #_init def _init_(self)  #initializing login_name as none self.login_name = 'none'.

<h3>What is a code in programming?</h3>

In laptop programming, laptop code refers back to the set of instructions, or a device of rules, written in a specific programming language (i.e., the supply code). It is likewise the time period used for the supply code after it's been processed via way of means of a compiler and made equipped to run at the laptop (i.e., the item code).

  1. CODE
  2. #elegance Login
  3. elegance Login:
  4. #_init_
  5. def _init_(self):
  6.  #initializing login_name as none
  7.  self.login_name = 'none'
  8.  #initializing login_password as none
  9.  self.login_password = 'none' #check_credentials()
  10. def check_credentials(self, user_login, user_passwd):
  11.  #initializing simlogin as 'Test'
  12.  simlogin = 'Test' #initializing simpass as 'Test'
  13.  simpass = 'test1234' #if consumer despatched an appropriate credentials
  14.  if user_login == simlogin and user_passwd == simpass:
  15.   #print "Successful login!"
  16.   print("Successful login!")
  17.   #returns False
  18.   go back False
  19.    #returns False
  20.   go back False
  21.   #timeout variable used for login attempts
  22. timeout = five
  23. #spark off for password
  24. password = input()
  25. #if now no longer legitimate login
  26.  else:
  27.   #decrements timeout
  28.  timeout = timeout - 1
  29.   #if timeout equals 0
  30.   if timeout == 0:
  31.    #prints "five failed login attempts. No extra login attempts."
  32.    print("five failed login attempts. No extra login attempts.")
  33.     #exits the loop
  34.    break
  35.  #spark off for consumer call
  36.  login = input()

Read more about the code:

brainly.com/question/4514135

#SPJ1

4 0
2 years ago
when connecting to a wireless local area network (wlan), what is the most important fact about the service set identifier (ssid)
iragen [17]

The most important fact about the service set identifier (SSID) is that all the end users and all access points (AP) must be configured with matching SSIDs.

<h3>What is SSID?</h3>

SSID is an acronym for service set identifier and it can be defined as the generic name given to a wireless local area network (WLAN) connection.

In Computer networking, the most important fact about the service set identifier (SSID) is that all the end users and all access points (AP) must be configured with matching SSIDs.

Read more on wireless local area network here: brainly.com/question/13697151

#SPJ11

4 0
2 years ago
Question #5
stepladder [879]

Answer:

books.append({5:2})

Explanation:

got it right on edge 2020

4 0
3 years ago
Read 2 more answers
The owner of a candle shop has asked for your help. The shop sells three types of candles as shown below:
Keith_Richards [23]

Answer:

import java.util.Scanner;

public class Main {

 public static void main(String[] args) {

   double total = 0;

   double fPrice, sPrice, tPrice;

   int firstN = 0, secdN = 0, thirdN = 0, fTime, sTime, tTime;

   int totalT = 0;

   isEnd = "n";

   for (;;){

       if (isEnd == "y"){

           break;

       }

       Scanner in = new Scanner(System.in);

       int option = in.nextInt();

       switch (option){

         case 1:

             fPrice = 2.50;

             fTime = 5;

             System.out.print("Enter number of items: ");

             firstN += in.nextInt();

             totalT += fTime * firstN;

             total += fPrice * firstN;

             break,

         case 2:

             sPrice = 3.75;

             sTime = 7;

             System.out.print("Enter number of items: ");

             secdN += in.nextInt();

             totalT += sTime * secdN;

             total += sPrice * secdN;

             break,

         case 3:

             tPrice = 5.99;

             tTime = 12;

             System.out.print("Enter number of items: ");

             thirdN += in.nextInt();

             totalT += tTime * thirdN ;

             total += tPrice * thirdN;

             break,

        default:

             System.out.println("Looking forward to the Weekend");

       }

       System.out.print("Do you want to end the order? y/n: ");

       isEnd = in.nextLine();

   }

   System.out.println("Number of Type 1 candles bought : "+firstN);

   System.out.println("Number of Type 2 candles bought : "+secdN);

   System.out.println("Number of Type 3 candles bought : "+thirdN);

   System.out.println("Total cost is : "+total);

   System.out.println("Total burn time is : "+totalT);

   double costPerBurn = (totatT * 60) / total;

   System.out.println("Cost per minute : "+ costPerBurn);

 }

}

Explanation:

The Java program creates a continuous for-loop statement that gets the candle type, price and amount ordered from a switch and accumulates the total cost and burn time of the candles bought and the cost per minute burn of the candles consecutively.

3 0
3 years ago
Explain what the problems with the implementation of the function are, and show a way to fix them.// return true if two C string
Nataly [62]

Answer:

The code is not dereferencing the pointers. You have to place an asterisk in front of the pointer to read the value the pointer points to.

Explanation:

So "if (str1 != str2)" must be "if (*str1 != *str2)".

likewise:

   while (*str1 != 0 && *str2 != 0)

and

     result = (*str1 == *str2);

7 0
3 years ago
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