The Municipality we be able to set up 597 street name boards with R2 left in the budget.
Data;
- Amount Budgeted = R80,000
- Cost of each board = R134
<h3>Number of Street Boards in the Budget</h3>
The number of streets boards that can be produced in the budget is calculated by dividing the total amount budgeted by the cost of each street board. This is done mathematically as
We would have a total of 597 street names on the budget with some amount left.
We can calculated this by multiplying 597 by 134 and then subtracting the value from R80,000
The Municipality we be able to set up 597 street name boards with R2 left in the budget.
Learn more on division of numbers here;
brainly.com/question/20301788
Answer:
Step-by-step explanation:
Fractions
Answer:
√3 is irrational
Step-by-step explanation:
The location of the third point of a triangle can be found using a rotation matrix to transform the coordinates of the given points.
<h3 /><h3>Location of point C</h3>
With reference to the attached figure, the slope of line AC is √3, an irrational number. This means the line AC <em>never passes through a point with integer coordinates</em>. (Any point with integer coordinates would be on a line with rational slope.)
<h3>Equilateral triangle</h3>
The line segments making up an equilateral triangle are separated by an angle of 60°. If two vertices are on grid squares, the third must be a rotation of one of them about the other through an angle of 60°. The rotation matrix is irrational, so the rotated point must have irrational coordinates.
The math of it is this. For rotation of (x, y) counterclockwise 60° about the origin, the transformation matrix is ...
![\left[\begin{array}{cc}\cos(60^\circ)&\sin(60^\circ)\\-\sin(60^\circ)&\cos(60^\circ)\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}x'\\y'\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ccos%2860%5E%5Ccirc%29%26%5Csin%2860%5E%5Ccirc%29%5C%5C-%5Csin%2860%5E%5Ccirc%29%26%5Ccos%2860%5E%5Ccirc%29%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%27%5C%5Cy%27%5Cend%7Barray%7D%5Cright%5D)
Cos(60°) is rational, but sin(60°) is not. For any non-zero rational values of x and y, the sum ...
cos(60°)·x + sin(60°)·y
will be irrational.
As in the attached diagram, if one of the coordinates of the rotated point (B) is zero, then one of the coordinates of its image (C) will be rational. The other image point coordinate cannot be rational.
Answer:
1. 16−6=10
2. 4⋅2+1
3. x÷25
4. y+8=40
Explanation:
This is an equation—two expressions are connected with an .This is an expression—no equal sign.
This is an expression—no equal sign.
This is an equation—two expressions are connected with an equal sign.
1.07 x 100 = 107%
hope this helps! :)
