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2 years ago

Which pair shows equivalent expressions?

Mathematics

2 answers:

Elodia [21]2 years ago

7 0

Answer:

C. 2(2/5x + 2) = 4/5 x +2

Explanation:

2 x 2/5= 4/5,

Multiply 2 by 2/5 which equals 4/5

After multipling you have 4/5 + 2.

C is the only answer that has 4/5 + 2 on both sides giving you,

4/5 x + 2 = 4/5 x +2

balu736 [363]2 years ago

3 0

Answer:

2(2/5x+2)= 2*2/5x + 2*2= 4/5x+4

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Answer:

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2 years ago

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Answer:

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3 years ago

an airplane travels 4688 kilometers against the wind in 8 hours and 5808 kilometers with the wind in the same amount of time. wh

Vladimir [108]

The speed of wind is 656 kmph and speed of plane is 70 kmph.

<u>SOLUTION: </u>

Given that, an air-plane travels 4688 kilometers against the wind in 8 hours

And 5808 kilometers with the wind in the same amount of time.

We have to find the rate of the plane in still air and the rate of wind

Now, let the speed of wind be a kmph and speed of plane be b kmph.

And we know that, $\text { distance }=\text { speed } \times \text { time }$

$\begin{array}{l}{\text { Then, while travelling with wind } \rightarrow 5808=(a+b) \times 8 \rightarrow a+b=726 \rightarrow a=726-b \rightarrow(1)} \\\\ {\text { While travelling against wind } \rightarrow 4688=(a-b) \times 8 \rightarrow a-b=586 \rightarrow(2)}\end{array}$

Substituting (1) in (2) we get,

$\Rightarrow 726-b-b = 586\Rightarrow -2b=586-726 \Rightarrow -2b=-140$

$\Rightarrow b=\frac{140}{2} \Rightarrowb=70\Rightarrow (3)$

On substituting (3) in (1) we get,

$a=726-70=656\Rightarrow a=656$

Hence, the speed of wind is 656 kmph and speed of plane is 70 kmph.

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3 years ago

Prove that JOYS with vertices j(1,1) o(2,-6) y(3,3) s(2,10) is a parallelogram

zmey [24]

For this you're going to use distance formula

D= square root of (x2-x1)^2 + (y2-y1)^2

To prove this is a parallelogram ALL sides must equal the same or two sides + two sides must be the same.

Find the distance of JO, YS, JS, and OS. If you have too find the distance of JY and OY. Using the formula above. Hope this helps you. If you need further help I can assist you with a problem step by step

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2 years ago