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Bingel [31]
2 years ago
13

Which expressions represent the product of exactly two factors?

Mathematics
1 answer:
Rufina [12.5K]2 years ago
8 0

i think

cy

is the answer

.

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How could I get rid of the 3 shown in equation 1?
Tems11 [23]

Answer:

Step-by-step explanation:

3 log 2+log (x-4)=log 2³+log (x-4)=log 8+log (x-4)=log 8(x-4)

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3 years ago
Multiply and simplify. (x - 3)(x2 + 3x + 9)
saul85 [17]
When you distribute and combine like terms, the result is x^3-27

4 0
3 years ago
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HELP!!!!!!!!!!!!GIVING BRAINLIEST!!!!!!!!!!!!!!!
notsponge [240]

Answer:

# of terms: 2

inConstant(s): might be wrong but i think its 5

Coefficient(s): might be y itself but i dont know

Highest degree: 5

I did what I could but this number is not factorable with rational numbers

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2 years ago
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The dimensions of a box that is a rectangular prism are 3 inches, 4 inches, and 6 inches. What is the length of the diagonal fro
Neporo4naja [7]

Answer:

7.8 in

Step-by-step explanation:

Given:-

- The dimension of rectangular prism:

                                   (3 x 4 x 6) inches

Find:-

What is the length of the diagonal from the point R to point S, to the nearest tenth of an inch?

Solution:-

- We will set up an origin with coordinates ( 0 , 0 , 0 ) at point R. Then the coordinates of point S would be ( 3 , 4 , 6 ).

- Then we will use the distance between two points formula in cartesian coordinate system:

                    Distance = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}

Where the coordinates of two points ( x1 , y1 , z1 ) & ( x2 , y2 , z2 ).

- Using R( 0 , 0 , 0 ) & S( 3 , 4 , 6 ), the distance |RS| would be:

                   |RS| = \sqrt{(0 - 3)^2 + (0 - 4)^2 + (0 - 6)^2}\\\\|RS| = \sqrt{ 9 + 16 + 36}\\\\|RS| = \sqrt{61} = 7.81024

- The distance |RS| to nearest 10th of an inch is = 7.8 in  

4 0
3 years ago
Math again yay!...Ew math
Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

f(x)=x^2

New function:

g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2

<u>Transformations</u>:

For a > 0

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}

\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}

If the parent function is <u>shifted ¹/₄ unit up</u>:

\implies g(x)=x^2+\dfrac{1}{4}

If the parent function is <u>shifted ¹/₄ unit down</u>:

\implies g(x)=x^2-\dfrac{1}{4}

If the parent function is <u>compressed vertically</u> by a factor of ¹/₄:

\implies g(x)=\dfrac{1}{4}x^2

If the parent function is <u>stretched horizontally</u> by a factor of ¹/₂:

\implies g(x)=\left(\dfrac{1}{2}x\right)^2

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

4 0
2 years ago
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