1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mamont248 [21]
3 years ago
14

So for translation when it says to move up 6 how do I solve that (ex. -6, -10)

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:

Well, the y axis is the up and down line of the graph. Therefore, if the translation says move up six, simply add six to the y axis (ex. -6, -10 move up six: -6, -4)! super simple, right? hope this helps!

You might be interested in
Shaun read 60 pages in 3/4 h. What is the unit rate that represents the number of pages Shaun can read in 1 h?
Alexus [3.1K]

Answer:

60=3/4

x=4/4

4/4÷1/4

4/4*4/1

4/1*1/1

4/1

4

3/4=12 because if 1/4 is 4 then 3/4 is 12

60=12

60÷12=5

5*4/20

60+20=80

Shaun will read 80 pages in 1 hour

I can only read 25 because i hate reading

4 0
3 years ago
I am so very confused, answers please.
Tasya [4]
I hate it here and also math sorry hint try a gaine a aging number too
7 0
3 years ago
Read 2 more answers
A rectangular storage container with an open top is to have a volume of 10 m3. The length of this base is twice the width. Mater
marshall27 [118]

Answer:

$ 327.08

Step-by-step explanation:

Let x = width of the container,

Then Length of the container = 2x

Let h = height of the container,

volume of the container can be calculated as length × width × height

= 2x × x × h

= 2x² h

Then we can say Volume =

= 2x² h=10

If we simplify inorder to get h

We have h= 5/x²

Then the area= (2L×h) +(2xh)

Where L is lenght

x= wish

h= height

= 2× 2x × h+ x× h

= 4x× 5/x + 2x × 5/x

Area = 30/x

Now, the area of the base = length × width

But from question, for the base costs $20 per square meter. Material for the sides costs $12 per square meter

Then the cost C(x)= 2x²× 20+30/x ×12

C(x)= 40x²+35/x²

If we differenciate wrt x we have

C(x)= 80-360/x²

If we equate C(x)=0the

80=360/x²

x= 1.651

If substitute to C(x)= 40x²+35/x²

C(x) = 40(1.651)² + 35/(1.651)²

We have cost= 327.08

6 0
3 years ago
If there is 5.2% sales tax on a pair of jeans? How much is the total tax?
masha68 [24]

How much is a pair of jeans? I can not answer the question if I do not know the price of the jeans.

5 0
3 years ago
Read 2 more answers
A cyclist estimates that he will bike 80 miles this week. He actually bikes 75.5 miles. What is the percent error of the cyclist
vazorg [7]

Answer:

6%

Step-by-step explanation:

Estimated distance = 80 miles

Actual distance covered = 75.5 miles

We need to find the percent error of the cyclist's estimate. Its formula is given by :

\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100

Put all the values,

\%=\dfrac{80-75.5}{75.5}\times 100\\\\=5.96\%

or

= 6%

So, the percentage error is 6%.

4 0
3 years ago
Read 2 more answers
Other questions:
  • How much will you save if you buy an item listed at $75.50 at a 25% discount?
    14·2 answers
  • What is 2x + 4=10 what is the answer?
    13·2 answers
  • Liam is setting up folding chairs for a meeting. If he arranges the chairs in 6 rows of the same length, he has 7 chairs left ov
    5·1 answer
  • I need help on this one please and thank you
    7·1 answer
  • Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
    9·1 answer
  • Which real world situation CANNOT be represented by
    14·1 answer
  • Find the mean of this set of numbers. 9, –6, –8, 11, –4, 10 a. 12 b. 8 c. 48 d. 2
    9·1 answer
  • Kelly sold digital cameras on her web site. She bought the cameras for $56 each and included a 65% markup to get the selling pri
    10·1 answer
  • Plz help! (due tonight!)
    13·1 answer
  • Help i will give brainliest
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!