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NeX [460]
3 years ago
15

Given a center of (3,-5) and a radius of 4, write an equation for the circle.

Mathematics
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:

(x-3)²+(y+5)²=16

Step-by-step explanation:

\large \boxed{ {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2} }

The equation above is an equation of circle with a centre at (h,k) and has radius = r

Substitute h = 3, k = -5 and r = 4 in the equation.

\large{ {(x - 3)}^{2}  +  {(y - ( - 5))}^{2}   =  {4}^{2} } \\  \large{ {(x - 3)}^{2}  +  {(y + 5)}^{2}  = 16}

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