Question

Given a center of (3,-5) and a radius of 4, write an equation for the circle.

Answer 1

Answer:

(x-3)²+(y+5)²=16

Step-by-step explanation:

$\large \boxed{ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} }$

The equation above is an equation of circle with a centre at (h,k) and has radius = r

Substitute h = 3, k = -5 and r = 4 in the equation.

$\large{ {(x - 3)}^{2} + {(y - ( - 5))}^{2} = {4}^{2} } \\ \large{ {(x - 3)}^{2} + {(y + 5)}^{2} = 16}$