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Yuliya22 [10]
3 years ago
11

for all values of x , a function f is defined by f(x)=x^2+7x+12 if f(a)=2, what could be the value of a?​

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

a = -2 or a = -5

Step-by-step explanation:

We want f(a) = a^2 + 7a + 12 = 2. We can subtract 2 from both sides of this equation to get a^2+7a+10=0. We can factor this to get that (a+2)(a+5)=0. When the product of two numbers is equal to zero, one of the numbers must be equal to zero. This means that either a + 2 = 0, in which case a = -2, or a + 5 = 0, in which case a = -5.

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Step-by-step explanation:

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<u>Step-by-step explanation:</u>

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<u>Step-by-step explanation:</u>

3^{2x}+3^{x+1}-4=0\\\\3^{2x}+3^x\cdot3^1-4=0\\\\\text{Let u = }3^x\\u^2+3u-4=0\\\\(u+4)(u-1)=0\\\\u+4=0\quad and\quad u-1=0\\u=-4\qquad and\quad u=1\\\\\text{Substitute u with }3^x\\3^x=-4\qquad and\quad 3^x=1\\\text{not possible}\ and\quad 3^x=3^0\\.\qquad \qquad \qquad \qquad \boxed{x=0}

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Answer:  No Solution

<u>Step-by-step explanation:</u>

4^x+6\cdot 2^x+8=0\\\\2\cdot 2^x+6\cdot 2^x+8=0\\\\\text{Let u = }2^x\\2u+6u+8=0\\8u+8=0\\8u=-8\\u=-1\\\\\text{Substitute u with }2^x\\2^x=-1\\\text{not possible}

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Answer:  No Solution

<u>Step-by-step explanation:</u>

<u>9^x=3^x-6\\\\3\cdot 3^x=1\cdot 3^x-6\\\\\text{Let u = }3^x\\\\3u=u-6\\2u=-6\\u=-3\\\\\text{Substitute u with }3^x\\3^x=-3\\\text{not possible}</u>

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3 years ago
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