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Yuliya22 [10]
2 years ago
11

for all values of x , a function f is defined by f(x)=x^2+7x+12 if f(a)=2, what could be the value of a?​

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
4 0

Answer:

a = -2 or a = -5

Step-by-step explanation:

We want f(a) = a^2 + 7a + 12 = 2. We can subtract 2 from both sides of this equation to get a^2+7a+10=0. We can factor this to get that (a+2)(a+5)=0. When the product of two numbers is equal to zero, one of the numbers must be equal to zero. This means that either a + 2 = 0, in which case a = -2, or a + 5 = 0, in which case a = -5.

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6 0
2 years ago
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Breann solved the system of equations below. What mistake did she make in her work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 −
goldfiish [28.3K]

Answer:

No mistake

Step-by-step explanation:

2x + y = 5

x - 2y = 10

y = 5 - 2x

x - 2(5 - 2x) = 10

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She made no mistake

You can check by plugging in x = 4 and y = -3 into the original equations . They fit exactly.


5 0
3 years ago
(x+7)^2+9=0<br><br> Find x with quadratics
Ne4ueva [31]

Answer:

x = -7 ±3i

Step-by-step explanation:

(x+7)^2+9=0

Subtract 9 from each side

(x+7)^2+9-9=0-9

(x+7)^2=-9

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(-9)

We know sqrt(ab) = sqrt(a) sqrt(b)

x+7 = ±sqrt(-1) sqrt(9)

We know that sqrt(-1) is the imaginary number i

x+7 = ±i *3

x+7 =±3i

Subtract 7 from each side

x+7-7 = -7 ±3i

x = -7 ±3i

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