Question

Hi, may someone help me with this question? Thank you!:) “If f(x) = x^2 + 7, find f(x+2)”

Answer 1

Answer:

=x^2 +4x+11

Step-by-step explanation:

f(x) = x^2 + 7,

Replace x with x+2

f(x+2) = (x+2)^2 + 7

         = (x+2)(x+2) +7

     FOIL

     = x^2 +2x+2x+4 +7

Combine like terms

    =x^2 +4x+11

Answer 2

Answer:

$f(x+2)=x^2+4x+11$

Step-by-step explanation:

In $f(x)=x^2+7$, for all values of $x$, we substitute $x$ (what is in the parentheses) into $x^2+7$ to output a $y$ value.

In $f(x+2)$, the term $(x+2)$ is in the parentheses. Therefore, substitute $(x+2)$ for $x$ in $x^2+7$ to find $f(x+2)$:

$f(x+2)=(x+2)^2+7$

Expand using $(a+b)^2=a^2+2ab+b^2$,

$f(x+2)=x^2+4x+4+7$

Combine like terms:

$\boxed{f(x+2)=x^2+4x+11}$