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3 years ago

Write the equation of the line for the graph shown below, please

Mathematics

2 answers:

iren [92.7K]3 years ago

7 0

For this question it’s asking for it in slope intercept form. So all you need to find is the slope and the y intercept.To find the y int look at where the line passes y. In this case it is y=4, then find slope by finding change in y/ change once which is 1/2, so you get y=1/2x+4

kondaur [170]3 years ago

3 0

Answer:

Given the proposed interrogate, as well as the graph provided, the correct answer is B. Y = 1/2 x + 4

Step-by-step explanation:

To evaluate such, a comprehension of linear Cartesian planes are obligated:

Slopes = rise/run

X- intercept: The peculiar point in which linear data is observed to intersect the x-axis.

Y- intercept: The peculiar point in which linear data is observed to intersect the y-axis.

Slope: 1/2 as for every individual space endeavored, a space of 2 to the right is required.

Y- intercept: (4,0)

Thus, the ameliorated answer to such interrogate is acknowledged as B. Y = 1/2 x + 4.

*I hope this helps.

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Determine the number and types of solutions for 6m^2-3m-4=0

Anna11 [10]

Answer:

2 real solutions

Step-by-step explanation:

Remember this messy thing?

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

The quadratic formula, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the type of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the discriminant. If it's non-negative, we'll have real roots, if it's negative, we'll have complex roots.

For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.

4 0

3 years ago

What is the transformation shown?

natta225 [31]

5 units left and 1 unit up

4 0

3 years ago

Mattie uses the discriminant to determine the number of zeros the q

enot [183]

Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac

there are 3 basic cases of what happens for different discriminants

1. if the discriminant is less than 0, then there are no real zeroes

2. if the discriminant is 0, then it has 1 zero

3. if the discriminant is greater than 0, it has 2 zeroes

so given

0=3x^2-7x+4

a=3,b=-7,c=4

thus the discriminant is (-7)^2-4(3)(4)=49-48=1

the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0

the answer is the equation has two zeroes because the discriminant is greater than 0

Step-by-step explanation:

3 0

3 years ago

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

6 0

3 years ago

Choose the polynomial that is written in standard form.

Annette [7]

When written in standard form, you have to order each term from the highest degree to the lowest degree.

b. x^4y² + 4x²y + 8x is your answer.

hope this helps, God bless!

4 0

3 years ago