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2 years ago

10 = 4 + c

Mathematics

1 answer:

IgorC [24]2 years ago

8 0

Step-by-step explanation:

I hope this helps Ans: B.

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In a closed system the momentum before a collision _ the momentum after a collision

Bas_tet [7]

It remain equal due to law of conservation of momentum

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3 years ago

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What is the slope of the graph of y = 5x - 6?

Amiraneli [1.4K]

your equation is written in y = mx + b

where m is your slope.

5 = m

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3 years ago

If θ is a first quadrant angle in standard position with P(u,v) = (3,4) evaluate cos 2 θ

zaharov [31]

We have to evaluate cos(2θ), knowing that θ is in the first quadrant and in standard position P(u,v) = (3,4).

We can picture this as:

We can write the relation:

$\tan \theta=\frac{4}{3}$

We now look at the identities to find cos(2θ):

$\cos (2\theta)=\frac{1-\tan^2(2\theta)}{1+\tan^2(2\theta)}$

There are many identities for cos(2θ), but this is expressed in the information we already know, so we can solve as:

$\begin{gathered} \cos (2\theta)=\frac{1-\tan^2(2\theta)}{1+\tan^2(2\theta)} \\ \cos (2\theta)=\frac{1-(\frac{4}{3})^2}{1+(\frac{4}{3})^2} \\ \cos (2\theta)=\frac{1-\frac{16}{9}}{1+\frac{16}{9}} \\ \cos (2\theta)=\frac{\frac{9-16}{9}}{\frac{9+16}{9}} \\ \cos (2\theta)=\frac{-7}{25} \end{gathered}$

Answer: cos(2θ) = -7/25

8 0

1 year ago

What is the center of the circle x² + y² = 25?

AlexFokin [52]

Answer:
The center is (0,0).
Explanation:
To find the center of a circle, you have to look at the x^2 and the y^2. Because there are no numbers with them in the equation, the center of the circle does not move. If the equation has been like (x-5)^2 + (y-2)^2=16, then the center of the circle would be at (5,2)

3 0

3 years ago

If sin theta = (sqrt 3)/2, which could not be the value of theta? A. 60 degrees B. 120 degrees C. 240 degrees D. 420 degrees I k

sineoko [7]

Your are right, $\pi /3$ and 2 $\pi /3$ are solutions.
Of course each of these solutions can be replaced by the same number +k2 $\pi$ (with k being an element of Z) since sin x=sin (x+k2 $\pi$ ) with k being an element of Z.
Those are angle measures expressed in radians.
If you translate in degrees you basically have to know that $\pi$ radian=180 degrees
so $\pi /3$ radian=60 degrees and 2 $\pi /3$ =120 degrees. So this two could be values of theta (A and B).
On top of that $\pi /3+2 \pi$ could also be a solution (x+k2 $\pi$ with k=1). This can be translated to 60+360=420 degrees which is solution D.
So C. 240 degrees is the only one that could not be a value of theta.

6 0

3 years ago