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ZanzabumX [31]
3 years ago
12

Find the difference of the polynomials given below and classify it in terms of degree and number of terms.

Mathematics
1 answer:
sergeinik [125]3 years ago
4 0

Given:

The polynomial is:

3n^2(n^2+4n-5)-(2n^2-14n+3)

To find:

The difference of the polynomials and classify it in terms of degree and number of terms.

Solution:

Consider the polynomial,

P(x)=3n^2(n^2+4n-5)-(2n^2-14n+3)

On simplification, we get

P(x)=3n^4+12n^3-15n^2-2n^2+14n-3

P(x)=3n^4+12n^3-17n^2+14n-3

The degree of this polynomial is 4 and the number of terms is 5.

Therefore, the correct option is D.

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and then the 30 expression will ADD to the 60 amount
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----------------------------------------------------------------------------------------
so...for August, that'll mean


\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7&#10;\\\\&#10;t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)&#10;\\\\&#10;t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o


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3 years ago
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