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ZanzabumX [31]
3 years ago
12

Find the difference of the polynomials given below and classify it in terms of degree and number of terms.

Mathematics
1 answer:
sergeinik [125]3 years ago
4 0

Given:

The polynomial is:

3n^2(n^2+4n-5)-(2n^2-14n+3)

To find:

The difference of the polynomials and classify it in terms of degree and number of terms.

Solution:

Consider the polynomial,

P(x)=3n^2(n^2+4n-5)-(2n^2-14n+3)

On simplification, we get

P(x)=3n^4+12n^3-15n^2-2n^2+14n-3

P(x)=3n^4+12n^3-17n^2+14n-3

The degree of this polynomial is 4 and the number of terms is 5.

Therefore, the correct option is D.

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Find the solution of this system of equations. Separate the x- and the y- values with a comma. X=6+y -8x+9y=-29
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Answer:

x= 25, y = 19

Step-by-step explanation:

Solve the following system:

{x = y + 6 | (equation 1)

9 y - 8 x = -29 | (equation 2)

Express the system in standard form:

{x - y = 6 | (equation 1)

-(8 x) + 9 y = -29 | (equation 2)

Swap equation 1 with equation 2:

{-(8 x) + 9 y = -29 | (equation 1)

x - y = 6 | (equation 2)

Add 1/8 × (equation 1) to equation 2:

{-(8 x) + 9 y = -29 | (equation 1)

0 x+y/8 = 19/8 | (equation 2)

Multiply equation 2 by 8:

{-(8 x) + 9 y = -29 | (equation 1)

0 x+y = 19 | (equation 2)

Subtract 9 × (equation 2) from equation 1:

{-(8 x)+0 y = -200 | (equation 1)

0 x+y = 19 | (equation 2)

Divide equation 1 by -8:

{x+0 y = 25 | (equation 1)

0 x+y = 19 | (equation 2)

Collect results:

Answer:  {x = 25 , y = 19

6 0
3 years ago
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