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3 years ago

Please help it due soon Show workings!

Mathematics

1 answer:

12345 [234]3 years ago

4 0

Answer:

Step-by-step explanation:

Alright so this problem is like that other one i did where line RQx2 is equal to line SU

First we set up an equation

x+3=x-2

because line RQ is only 1/2 of line SU we multiple its side by 2 to get the new equation of

x+3=2x-4

step 1 subtract each side by 2x

-1x+3=-4

step 2 subtract each side by 3

-1x=-7

divide each side by -1

x=7

Next we plug in x (7) so 7-2=5

line RQ=5

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How do I find the slope of a perpendicular line?

Licemer1 [7]

Yes, math can be challenging sometimes (mostly due to the horrible way its taught by teachers but I wont go on a rant about that today).

The Slope of a parallel line is obviously going to have the same slope as the line it is parallel to, which you already know.

But for perpendicular, how would we figure that out?

First, you need to understand whats going on. Picture a linear line. Now, look at the (0,0) point. To make it perpendicular, it must form 90 degrees with the other line. Now, to get the answer for a perpendicular line, you need to remember two steps.

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3 years ago

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Triss [41]

Answer: D this would be after you have simplified it.

Step-by-step explanation:

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3 years ago

Read 2 more answers

a. Calculate the volume of the solid of revolution created by rotating the curve y = 3 + 3 exp(-5 x) about the x-axis, for x bet

miskamm [114]

Answer:

A) The volume of solid is 18π cubic unit.

B) The volume of sphere is $\dfrac{4}{3}\pi r^3$

a = -r , b = r , $f(x)=\sqrt{r^2-x^2}$ and $V=\dfrac{4}{3}\pi r^3$

Solution A)

The given curve, $y=3+3e^{-5x}$ rotate about x-axis between 2 to 4.

Please find attachment for solid figure or rotation.

Using disk method to find the volume rotation about x-axis

$V=\int_a^b\pi R^2dx$

where, a = 2, b= 4 , $R=y=3+3e^{-5x}$ and dx is thickness of disk.

$V=\int_2^4\pi (3+3e^{-5x})^2dx$

$V=9\pi\int_2^4(1+e^{-10x}+2e^{-5x})dx$

$V=9\pi(x-\dfrac{1}{10}e^{-10x}-\dfrac{2}{5}e^{-5x})|_2^4)$

$V=9\pi(4-\dfrac{1}{10}e^{-40}-\dfrac{2}{5}e^{-20}-2+\dfrac{1}{10}e^{-20}-\dfrac{2}{5}e^{-10}))$

$V=9\pi (2-0)$

$V=18\pi$

Hence, the volume of solid is 18π cubic unit

Solution B)

The equation of circle of radius r and centered at origin (0,0).

$x^2+y^2=r^2$

$y=\sqrt{r^2-x^2}$

The solid form is sphere of radius r.

Using disk method, to find volume of solid

$V=\int_a^b\pi R^2dx$

where, a = -r, b = r , $R=y=\sqrt{r^2-x^2}$ and dx is thickness of disk.

$V=\int_{-r}^r\pi (r^2-x^2)dx$

$V=\pi(r^2x-\dfrac{x^3}{3})|_{-r}^r$

$V=\pi(2r^3-\dfrac{2r^3}{3})$

$V=\dfrac{4}{3}\pi r^3$

Hence, the volume of sphere is $\dfrac{4}{3}\pi r^3$

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3 years ago

What is the volume of the cylinder below?

Lera25 [3.4K]

Answer: The answer is 972.

Step-by-step explanation: The formula for the volume if a cylinder is πr2h and the radius is 9 and to the second power is 81. So then the radius multiplied by the height (which is 12) is 972 which is the answer.

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3 years ago

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galben [10]

Answer:

Step-by-step explanation:

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