We are given a graph of a quadratic function y = f(x) .
We need to find the solution set of the given graph of a quadratic function .
<em>Note: Solution of a function the values of x-coordinates, where graph cut the x-axis.</em>
For the shown graph, we can see that parabola in the graph doesn't cut the x-axis at any point.
It cuts only y-axis.
Because solution of a graph is only the values of x-coordinates, where graph cut the x-axis. Therefore, there would not by any solution of the quadratic function y = f(x).
<h3>So, the correct option is 2nd option :∅.</h3>
step-by-step.
x
3
+10=15
Step 1: Simplify both sides of the equation.
1
3
x+10=15
Step 2: Subtract 10 from both sides.
1
3
x+10−10=15−10
1
3
x=5
Step 3: Multiply both sides by 3.
3*(
1
3
x)=(3)*(5)
x=15
Answer:
x=15
Answer:
78.57
Step-by-step explanation:
Radius is 5 feet
Area of circle is pi*r Squared
22/7*5*5
78.57 square feet
Answer:
<h2>-33x - 82</h2>
Step-by-step explanation:
Use
PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
and the distributive property a(b + c) = ab + ac.
![1)\qquad5(x+3)=5x+15\\\\2)\qquad x+5(x+3)=x+5x+15=6x+15\\\\3)\qquad2[x+5(x+3)]=2(6x+15)=12x+30\\\\4)\qquad x-2[x+5(x+3)]=x-(12x+30)=x-12x-30=-11x-30\\\\5)\qquad3\{x-2[x+5(x+3)]\}=3(-11x-30)=-33x-90\\\\6)\qquad8+3\{x-2[x+5(x+3)]\}=8+(-33x-90)=-33x-82](https://tex.z-dn.net/?f=1%29%5Cqquad5%28x%2B3%29%3D5x%2B15%5C%5C%5C%5C2%29%5Cqquad%20x%2B5%28x%2B3%29%3Dx%2B5x%2B15%3D6x%2B15%5C%5C%5C%5C3%29%5Cqquad2%5Bx%2B5%28x%2B3%29%5D%3D2%286x%2B15%29%3D12x%2B30%5C%5C%5C%5C4%29%5Cqquad%20x-2%5Bx%2B5%28x%2B3%29%5D%3Dx-%2812x%2B30%29%3Dx-12x-30%3D-11x-30%5C%5C%5C%5C5%29%5Cqquad3%5C%7Bx-2%5Bx%2B5%28x%2B3%29%5D%5C%7D%3D3%28-11x-30%29%3D-33x-90%5C%5C%5C%5C6%29%5Cqquad8%2B3%5C%7Bx-2%5Bx%2B5%28x%2B3%29%5D%5C%7D%3D8%2B%28-33x-90%29%3D-33x-82)