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Andrews [41]
2 years ago
12

graph of a function is alone that passes through the points (0,1) and (3,10) write an equation in the form y=Mx+b. For this func

tion
Mathematics
1 answer:
nadya68 [22]2 years ago
8 0

Answer:

y = 3x + 1

Step-by-step explanation:

(0,1) so that is the b

the rate of change is 9/3 so the m is 3

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A graph of a quadratic function y = f(x) is shown below.
spin [16.1K]

We are given a graph of a quadratic function y = f(x) .

We need to find the solution set of the given graph of a quadratic function .

<em>Note: Solution of a function the values of x-coordinates, where graph cut the x-axis.</em>

For the shown graph, we can see that parabola in the graph doesn't cut the x-axis at any point.

It cuts only y-axis.

Because solution of a graph is only the values of x-coordinates, where graph cut the x-axis. Therefore, there would not by any solution of the quadratic function y = f(x).

<h3>So, the correct option is 2nd option :∅.</h3>
8 0
3 years ago
Read 2 more answers
How do i solve x/3+10=15
yaroslaw [1]

step-by-step.

x

3

+10=15

Step 1: Simplify both sides of the equation.

1

3

x+10=15

Step 2: Subtract 10 from both sides.

1

3

x+10−10=15−10

1

3

x=5

Step 3: Multiply both sides by 3.

3*(

1

3

x)=(3)*(5)

x=15

Answer:

x=15

8 0
3 years ago
A lawn sprinkler sprays water 5 ft in every direction as it rotates. What is the area of the sprinkled lawn?
Karolina [17]

Answer:

78.57

Step-by-step explanation:

Radius is 5 feet

Area of circle is pi*r  Squared

22/7*5*5

78.57 square feet

6 0
2 years ago
Read 2 more answers
HELP ASAP!!
Monica [59]
B because it makes sense
3 0
3 years ago
Read 2 more answers
Simplify 8 + 3{x - 2[x + 5(x + 3)]}.<br><br> -33x + 82<br> 33x - 82<br> -33x - 82
77julia77 [94]

Answer:

<h2>-33x - 82</h2>

Step-by-step explanation:

Use

PEMDAS:

P      Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

and the distributive property a(b + c) = ab + ac.

1)\qquad5(x+3)=5x+15\\\\2)\qquad x+5(x+3)=x+5x+15=6x+15\\\\3)\qquad2[x+5(x+3)]=2(6x+15)=12x+30\\\\4)\qquad x-2[x+5(x+3)]=x-(12x+30)=x-12x-30=-11x-30\\\\5)\qquad3\{x-2[x+5(x+3)]\}=3(-11x-30)=-33x-90\\\\6)\qquad8+3\{x-2[x+5(x+3)]\}=8+(-33x-90)=-33x-82

5 0
3 years ago
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