Y = 2x - 3 . . . (1)
y = -2x + 5 . . . (2)
Equating (1) and (2),
2x - 3 = -2x + 5
2x + 2x = 5 + 3
4x = 8
x = 8/4 = 2
x = 2
y = 2(2) - 3 = 4 - 3 = 1
y = 1
Solution = (2, 1)
The height of the can for this case is given by:
h = 40 mm
The radius of the can is given by:
r = (1 3/8) * h
Substituting values:
r = (1 3/8) * 40
r = 55 mm
Therefore, the diameter of the can is:
d = 2 * r
d = 2 * 55
d = 110 mm
Answer:
The diameter of the can will be:
d = 110 mm
Answer:
A. 4.25p + 3.79c
b. 28.83
Step-by-step explanation:
4.25 x 5 = 21.25
3.79 x 2 = 7.58
Answer:
A, B, C, D
Step-by-step explanation:
They All add up to 360
Answer:
289
Step-by-step explanation:
We don't need 
at all for this.
We will need to know 
before continuing...
can be found by replacing 
in 
with 
:
-------------------
Now let's find ![[f(4)]^2](https://tex.z-dn.net/?f=%5Bf%284%29%5D%5E2)
:
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