Answer:
4 kg of sugar would contain 
crystals.
Step-by-step explanation:
Given that 3kg of sugar contains 9 × 10⁸ crystals, let "x" represent the number of sugar crystals 4kg of sugar would contain.
Thus, set up a proportion as follows:
3 kg : 9 × 10⁸ = 4 kg : x
Solve for x. Cross multiply.
Divide both sides by 3
4 kg of sugar would contain crystals.
The height and radius that will give us the smallest amount of paper, should have should have the perfect dimension, in that the diameter should be equal to the height. thus let the diameter be x, the height will be x and the radius will be x/2
thus the volume of the cone will be:
V=1/3πr^2h
=1/3*π*(x/2)^2*x
=0.262x^3
hence the value of x will be:
33=0.262x^3
x^3=125.95
x=(125.95)^(1/3)
x=5.0126=5.01 cm
thus the diameter=height=5.01cm
<span>19/10 simplifies to: 19/10 or 1.9</span>
The answer is :A. x=3 or x=-7
I think its b
that's the answer for me cause I got that question before and I remember saying B and the teacher said it was right
