Word Bank for #4-8: Read the passage and fill in the blanks using the following terms.
1 answer:
Answer:
<h2>option d Meiosis</h2>
Explanation:
Term Meaning
Gamete A sex cell (in humans: sperm for males, and eggs for females)
Meiosis A two-step process of cell division that is used to make gametes (sex cells)
Crossing over Process in which homologous chromosomes trade parts
Interphase Phase of the cell cycle where the cell grows and makes a copy of its DNA
Homologous chromosomes Set of chromosomes (one from each parent), that are very similar to one another and have the same size/shape
Sister chromatids Two halves of a duplicated chromosome
Diploid (2n) Cell that contains two sets of homologous chromosomes
Haploid (n) Cell that contains only a single set of genes
Meiosis
The purpose of meiosis is to produce gametes, or sex cells. During meiosis, four daughter cells are produced, each of which are haploid (containing half as many chromosomes as the parent cell).
Stages of meiosis
Meiosis contains two separate cell divisions, meaning that one parent cell can produce four gametes (eggs in females, sperm in males). In each round of division, cells go through four stages: prophase, metaphase, anaphase, and telophase.
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Using the binomial distribution, it is found that there is a 0.9513 = 95.13% probability that less than three of these mortgages are delinquent.
For each mortgage, there are only two possible outcomes, either they are delinquent or they are not. The probability of a mortgage being delinquent is independent of any other mortgage, hence the binomial distribution is used to solve this question.
<h3>What is the binomial distribution formula?</h3>The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 11% of mortgages were delinquent last year, hence p = 0.11.
- A random sample of eight mortgages was selected, hence n = 8.
The probability that less than three of these mortgages are delinquent is:
In which:
Then:
0.9513 = 95.13% probability that less than three of these mortgages are delinquent.
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