Answer:
no
Step-by-step explanation:
We want to compare the pot holder hole dimension to the pot dimension. The hole diameter is the overall pot holder diameter less the wall thickness on either side:
hole diameter = (20 1/5) -2(1 2/7) = 20 -2(1) +1/5 -(2)(2/7)
= 18 +(1/5 -4/7) = 18 +(7 -20)/35 = 18 -13/35
= 17 22/35 . . . . cm
We want to compare this to 17 4/5. We can do that by using a common denominator for the fractions.
17 4/5 = 17 + (4/5)(7/7) = 17 28/35 . . . . cm
The pot has a diameter of 17 28/35 cm; the pot holder has a hole diameter of 17 22/35 cm, so <em>the hole is smaller than the pot</em>.
The pot will not fit into the plant pot holder.
_____
You can use your calculator to find the free space around the pot by computing ...
20 1/5 -2(1 2/7) -17 4/5 = free space = -6/35 . . . . cm
Negative space means the pot is larger than the hole.
Answer:

Step-by-step explanation:
observe
||a–b+c|| = ||a+b+c||
(a-b+c)² = (a+b+c)²
(a+b+c)² – (a-b+c)² = 0
((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0
(2a+2c)(2b) = 0
(a+c)b = 0
a•b + c•b = 0
||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0

Answer:
D
Step-by-step explanation:
Answer:
The answer is A. Step 1
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