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Mama L [17]
3 years ago
15

True or False?

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0

Answer: true

Step-by-step explanation:

otez555 [7]3 years ago
5 0
No,this is not the correct formula
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An insurance company study shows that 9% of U. S. adults have diabetes. Suppose 8 US adults are selected at random. LetX be the
Bogdan [553]

Using the binomial distribution, it is found that:

  • The mean of X is of 0.72.
  • The standard deviation of X is of 0.81.

<h3>What is the binomial probability distribution?</h3>

It is the probability of exactly <u>x successes on n repeated trials, with p probability </u>of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

For this problem, the parameters are given as follows:

n = 8, p = 0.09.

Hence the mean and the standard deviation are, respectively:

  • E(X) = np = 8 x 0.09 = 0.72.
  • \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{8 \times 0.09 \times 0.91} = 0.81

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

3 0
2 years ago
If 2x + 6 =4x-4 then x=
Rina8888 [55]
The correct answer would be x = 4
6 0
3 years ago
Help this is one thats to hard
aliina [53]

We are given the following sequence:

6,-20,58

The formula that we can use to obtain the sequence is the following:

a_n=-3a_{n-1}-2,a_1=6

Because when we replace the given terms we get:

\begin{gathered} a_2=-3(6)-2 \\ a_2=-18-2 \\ a_2=-20 \end{gathered}

For the next term:

\begin{gathered} a_3=-3(-20)-2 \\ a_3=60-2 \\ a_3=58 \end{gathered}

6 0
2 years ago
Find the area of each shaded segment in nearest tenth.
shepuryov [24]

Answer:

Denote the center of circle as O, the 2 endpoints of shaded segment as AB, then we have:

section OAB area = pi x radius^2 x (120/360) = pi x 6^2 x (1/3) = 37.7 (cm2)

Considering triangle OAB, we have OA = OB = radius, angle AOB = 120 deg. Denote OH as the height of triangle. H lies on AB.

=> Applying cosine and sine theorem in right triangle AHO:

OH = OA x cos 60 = 6 x (1/2) = 3 (cm)

AH = OA x sin 60 = 6 x (sqrt3)/2 = 5.2 (cm)

=> triangle AOB area:

A = triangle AOH area x 2

   = AH x OH x (1/2) x 2 = 3 x 5.2 x (1/2) x 2 = 15.6 (cm2)

=> shaded segment area = section OAB area - triangle AOB

                                          = 37.7 - 15.6 = ~21.1 (cm2)

Hope this helps!

:)

7 0
3 years ago
Integrals using U sub. Please show steps so I can learn too :)
Romashka [77]

Answer:

\frac{arctan^2(x)}{2}

Step-by-step explanation:

For this question, set u = arctan(x).  This would be the easiest way because the derivative of arctan(x) is \frac{1}{x^2+1} which is what we have.  Before setting u, always look at the question and think about possible derivatives.

\int\frac{arctanx}{x^2+1}dx \ Let \ u = arctan(x)\\\\\\u = arctan(x) \ \ \ du = \frac{1}{x^2+1}dx\\

Next, plug in u and du.

\int (arctan(x)*\frac{1}{x^2+1})dx (rearranging)

\int u\ du

= \frac{u^2}{2} = \frac{1}{2}u^2

Substitute arctan(x) back in for u and add +C.

\frac{arctan^2(x)}{2}+C

7 0
3 years ago
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