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skad [1K]
3 years ago
10

Please help. Question #12

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
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<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

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                      W = 10 - L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

      dA = 0

      10 - 2 L = 0

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      W = 10 - 5 = 5 m

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Maximum area is 25 m²

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