All categories

3 years ago

Please help this is important

Mathematics

2 answers:

Galina-37 [17]3 years ago

5 0

Answer:

First blank - SSS congruent condition

Second blank - Congruent 

docker41 [41]3 years ago

5 0

Answer: This looks famiiar to me btw which school do u go to? :)

You might be interested in

Which term in the quotient of this expression contains an error?

Savatey [412]

Answer:

The + 78 :- it should be + 60.

Step-by-step explanation:

Long division:-

x - 3 )4x^4 - 6x^3 + 0x^2 + 6x + 3 ( 4x^3 + 6x^2 + 18x + 60 <--- Quotient.

4x^4 - 12x^3

6x^3 + 0x^2

6x^2 - 18x^2

18x^2 + 6x

18x^2 - 54x

60x + 3

60x - 180

183

7 0

3 years ago

A geologist has collected 5 specimens of basaltic rock and 7 specimens of granite. The geologist instructs a laboratory assistan

MaRussiya [10]

The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:

$E(X) = 5.25, Var(X) = 0.5966$
P(X < 6) = 0.9545
P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The mean and the variance are:

$\mu = \frac{nk}{N}$

$\sigma^2 = \frac{nk(N-k)(N-n)}{N^2(N-1)}$

We have that:

5 + 7 = 12 rocks, which means that $N = 12$

9 are chosen, which means that $n = 9$

7 are granite, which means that $k = 7$

Question a:

$E(X) = \mu = \frac{9\times7}{12} = 5.25$

$Var(X) = \sigma^2 = \frac{9\times7(12-7)(12-9)}{12^2(12-1)} = 0.5966$

Thus:

$E(X) = 5.25, Var(X) = 0.5966$

Question b:

Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 4) = h(4,12,9,7) = \frac{C_{7,4}*C_{5,5}}{C_{12,9}} = 0.1591$

$P(X = 5) = h(5,12,9,7) = \frac{C_{7,5}*C_{5,4}}{C_{12,9}} = 0.4773$

$P(X = 6) = h(6,12,9,7) = \frac{C_{7,6}*C_{5,3}}{C_{12,9}} = 0.3181$

Thus

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1591 + 0.4773 + 0.3181 = 0.9545$

So P(X < 6) = 0.9545.

Question c:

5 of basaltic and 4 of granite: 0.1591 probability.

7 of granite is P(X = 7), in which

$P(X = 7) = h(7,12,9,7) = \frac{C_{7,7}*C_{5,2}}{C_{12,9}} = 0.0455$

0.1591 + 0.0455 = 0.2046, thus:

P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

A similar question is found at brainly.com/question/24008577

5 0

3 years ago

1,3 1,5 1,7 1,9 is this a function . what is the domain and the range

Anna [14]

f(x) = {(1,3), (1,5), (1,7), (1,9)}

Domain = 1, 1, 1, 1

Range = 3, 5, 7, 9

7 0

3 years ago

Read 2 more answers

galina1969 [7]

Answer: (x+3)^2+(y-4)^2=49

The answer is b :)

Step-by-step explanation:

7 0

3 years ago

H/2 + 21 - k if h=20 and k=89

Hoochie [10]

$\huge\text{Hey there!}$

$\mathsf{\dfrac{h}{2} + 21 - k\ if\ h=20\ and\ k=89}$

$\textsf{If h = 20 and k = 89, the SUBSTITUTE it for where they are in the equation}$

$\mathsf{\dfrac{10}{2}+21 - 89}$

$\mathsf{\dfrac{20}{2}= \bf 10}$

$\mathsf{\bold{10}+21 - 89}$

$\mathsf{10+21=\bf 31}$

$\mathsf{\bold{31}-89= \underline{ANSWER}}$

$\mathsf{= \bf -58}$

$\boxed{\boxed{\large\text{Answer: \huge \bf -58}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

3 years ago