Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Hope this helps ;)
The ratio of the length of the room to its area is
Answer:
321
Step-by-step explanation:
Yes, they both are 2/7
Proof: Left-hand side
Simplify the following:
12/42
The gcd of 12 and 42 is 6, so 12/42 = (6×2)/(6×7) = 6/6×2/7 = 2/7:
Answer: 2/7
Right-hand side:
Simplify the following:
10/35
The gcd of 10 and 35 is 5, so 10/35 = (5×2)/(5×7) = 5/5×2/7 = 2/7:
Answer: 2/7
