3 years ago

15 POINTS PLEASE HELP

Mathematics

1 answer:

adoni [48]3 years ago

5 0

hey....I didn't know the answer to question 6.

I know my handwriting sucks....if you have trouble understanding my handwriting

tell me...I ll explain it to you

You might be interested in

One photoshop charges $0.36 per print. Another photoshop charges $2.52 plus $0.08 per print. Juan finds that the cost of printin

Rufina [12.5K]

He would have to print 9

7 0

3 years ago

Read 2 more answers

Isaac is working as a security guard. He earns $8.45 an hour. He earns double time for any overtime over 40 hours. Last week he

andreev551 [17]

Answer:

$405.60

Step-by-step explanation:

If Isaac works for 40 hours will earn $8.45×40=$388. Since he worked 4 extra hours, he will earn $8.45×2×4 since he worked 4 extra hours. $8.45×2=$16.90, which is the amount he earns for every extra hour he works. $16.90×4=$67.60. Now if we add $67.60+$388=$405.60.

Hope this helps!

6 0

3 years ago

If f(x) = 0, what is x? 0 only –6 only –2, 1, or 3 only –6, –2, 1, or 3 only

Angelina_Jolie [31]

Answer:

answer will be 0

plz mark me as brainliest

8 0

3 years ago

Wesley office had already recycled 37 kilograms this year before starting a new recycling plan, and the new plan will have the o

borishaifa [10]

Answer:

37 kilograms alr recycled this year

Plan:

1 kilogram each week

After 13 weeks he would of recycled 13 kilograms

37+13=50

In total his office wesley's have recycled 50 kilograms of paper

Hope this helps

8 0

3 years ago

Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and

pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

$104=1\times 2\times 2\times 2\times 13$

$88=1\times 2\times 2\times 2\times 11$

Form above , we can say that common factors are :

$HCF=2\times 2\times 2=8$

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0

3 years ago

Read 2 more answers