A. √(0.8^2) + (0.6^2) = √1 = 1 => OK
<span>b.(-2/3,√ 5/3) = √(-2/3)^2 + 5/9) = √(4/9 +5/9) = √1 = 1 => OK
c.(√ 3/2, 1/3) = √(3/4 + 1/9) < 1 => it is inside the unit circle
d.(1,1)
= √(1 + 1) = √2 > 1 => NO. This point is beyond the limits of the unit circle.</span>
Slope = -2; y-intercept = 30
points: (2, 26); (3, 24)
Volume of a cone = <span>πr^2(h/3)
r=6
h=27
v = </span><span>π(6^2)27/3
v = </span><span>π (36)(9)
v=</span><span>π324 in. cubed
or
v=1,017.36 in. cubed </span>
Answer:
y = 10x + 7
Step-by-step explanation:
Answer: 11
Step-by-step explanation: The sum of 15 and six times t will be 15 + 6t = 81.
Now, you subtract 15 from both sides to isolate the constants from the variables on the left side and on the other side and you will end up with 6t = 66. Then, you divide 6 from both sides to finally isolate the numbers from the variable and 66 divided by 6 would equal 11
Hope this Helps :)
