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Ugo [173]
2 years ago
15

Strategies for Rational Numbers Please help me

Mathematics
1 answer:
OLEGan [10]2 years ago
3 0

Answer:

i think its the same thing

Step-by-step explanation:

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What is the sign of the product (−4)(6)(9)(3)?
Natalija [7]
The product is -648. This is because (-6)(4) is a negative product and (9)(3) is a positive product. A negative and a positive product equals a negative outcome. The third option is correct
4 0
3 years ago
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The half-life of Radium-223 is 11.43 years. What is the annual decay rate? Express the result to four decimal places.
mestny [16]

Answer:

Below

Step-by-step explanation:

e^(-kt) = 1/2     when t = 11.43

so  k = .060642797

e^ (- .060642797 * 1) = .9411  <====   is left after one year

             which means the decay in one year is

                  1 - .9411 = .05884 = 5.88% per year

3 0
1 year ago
How many minutes in p hours​
Softa [21]

Answer:

theres 60 minutes in an hour

Step-by-step explanation:

4 0
3 years ago
The perimeters of the square and the regular pentagon are equal.
Dmitry [639]
Since the perimeters are equal then:

(3x + 3) * 4 = (x + 8) * 5
12x + 12 = 5x + 40
7x = 28
x =4
Perimeter of square = (3*4 + 3) * 4 =
(12 + 3) * 4 = 60

Perimeter of pentagon = (4 + 8) * 5 =
(12) * 5 = 60

The answer is 60





6 0
3 years ago
Read 2 more answers
This figure is made up of a quadrilateral and a semicircle.
vodomira [7]

Here the figure is made up of a quadrilateral and a semi circle.

ABCD is the quadrilateral here. We will find the sides of the quadrilateral by using the distance formula.

If (x₁, y₁) and (x₂, y₂) are two points given, then the distance between two points by using distance formula is,

d =\sqrt({ x_{1}-x_{2})^2  +( y_{1} -y_{2}  )^2}

The co-ordinate of A is (-1,2) and co-ordinate of B is (-2,-1).

So the length of side AB = \sqrt{(-1-(-2))^2+(2-(-1))^2}

=\sqrt{(-1+2)^2+(2+1)^2}(As negative times negative is positive)

= \sqrt{(1)^2+(3)^2} =\sqrt{1+9}  =\sqrt{10}

The co-ordinate of C is (4,-3) and D is (5,0)

The length of side CD

= \sqrt(4-5)^2+(-3-0)^2}

= \sqrt{(-1)^2+(-3)^2}

= \sqrt{1+9} =\sqrt{10}

So the sides AB and CD are equal.

The length of side AD

= \sqrt{(-1-5)^2+(2-0)^2}

= \sqrt{(-6)^2+(2)^2} =\sqrt{36+4} =\sqrt{40}

The length of side BC

= \sqrt{(-2-4)^2+(-1-(-3))^2}

= \sqrt{(-2-4)^2+(-1+3)^2}

= \sqrt{(-6)^2+(2)^2}=\sqrt{36+4} =\sqrt{40}

So the lengths of the sides AD and BC are equal.

So the quadrilateral is a rectangle whose length is \sqrt{40} and width is \sqrt{10}.

Area of a rectangle = length × width

= (\sqrt{40}) (\sqrt{10})

= \sqrt{(40)(10)}=\sqrt{400}

= 20 unit^2

Now the diameter of the semicircle is the side AD = \sqrt{40}

So, the radius of the semi-circle = \frac{\sqrt{40}}{2}

= \frac{\sqrt{(4)(10)}}{2}

= \frac{(\sqrt{4})(\sqrt{10})}{2}

= \frac{2\sqrt{10}}{2} = \sqrt{10}

Area of semi-circle = \frac{1}{2} \pi r^2, where r is the radius.

= \frac{1}{2} \pi  (\sqrt{10})^2

= \frac{1}{2} \pi   (10)

= \frac{(\pi)(10)}{2}

= \frac{10\pi}{2}   = 5\pi = 15.7 unit^2 ( Approximately taken to the nearest tenth)

Total area of the figure = (20+15.7) unit^2 = 35.7 unit^2

We have got the required answer.

Option a is correct here.

3 0
3 years ago
Read 2 more answers
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